Question

我有一个返回表的函数。我的左连接表中有一个字段，该字段导致某些结果重复。这导致总计错误。我需要以这种方式显示它，因为它已在另一个应用程序的CSV结果中使用。


Job Number   |   Job Total    |   Supp Ref (from a Left joined Table)
---------------------------------------------------------------------
4556              101.60          I450666
4556              101.60          P500694
4557              67.70           I88950A
4558              83.15           595900339
4559              132.00          O9995044
4559              132.00          I554112
4559              132.00          33209A00
4559              132.00          669554


Create Function JobDetails
{
 ... <Bunch of Params>
...
@JobDate DateTime
}
Returns Table 
as 
Return

Select 
JOBNUMBER, 
JOBTOTAL, 
SUPPREF
from 
(Select J.JOBNO as JOBNUMBER, Sum(J.TOTAL) as JobTotal,
S.REFNO = SUPPREF
from
JOBS J Left Join
 JOBNOTES S on J.ID = S=JOBID
Where J.DATE >=@JobDate
Group by J.JOBNO, S.REFNO 
) as JobTotals

我希望看到的是

Job Number   |   Job Total    |   Supp Ref (from a Left joined Table)
---------------------------------------------------------------------
4556              101.60          I450666
4556                              P500694
4557              67.70           I88950A
4558              83.15           595900339
4559              132.00          O9995044
4559                              I554112
4559                              33209A00
4559                              669554

我知道这是有可能的，但是我不确定该怎么做。感谢您的帮助。

Answer 1

首先，您的子查询不是必需的：

Select J.JOBNO as JOBNUMBER, Sum(J.TOTAL) as JobTotal,
       S.REFNO as SUPPREF
from JOBS J Left Join
     JOBNOTES S
     on J.ID = S.JOBID
Where J.DATE >= @JobDate
Group by J.JOBNO, S.REFNO

您可以使用窗口功能执行所需的操作：

Select J.JOBNO as JOBNUMBER,
       (CASE WHEN row_number() over (partition by J.JOBNO order by S.REFNO) = 1
             THEN Sum(J.TOTAL)
        END) as JobTotal,
       S.REFNO as SUPPREF
from JOBS J Left Join
     JOBNOTES S
     on J.ID = S.JOBID
Where J.DATE >= @JobDate
Group by J.JOBNO, S.REFNO

返回第一行值但后续值保留为空的SQL查询

1 个答案: