Question

下面是用于重新加载上一页的按钮单击处理程序，但其次不能使用。

(First page)
 private void button4_Click(object sender, EventArgs e)
        {
            this.DialogResult = System.Windows.Forms.DialogResult.OK;
            selectdata sl = new selectdata();
            sl.Show();
            Visible = false;
        }

(second Page)
    private void button1_Click(object sender, EventArgs e)
                List<CommonValue> CV = new List<CommonValue>();

                foreach (DataGridViewRow item in dataGridView1.Rows)
                {
                    if (Convert.ToBoolean(item.Cells[0].Value))
                    {
                        CV.Add(new CommonValue
                        {    
                            Id = item.Cells[1].Value.ToString(),
                            Name = item.Cells[2].Value.ToString(),
                            description = item.Cells[3].Value.ToString(),
                            qty = item.Cells[4].Value.ToString(),
                            uom = item.Cells[5].Value.ToString(),
                            price = item.Cells[6].Value.ToString(),
                        });
                    }    
                }
                this.DialogResult = System.Windows.Forms.DialogResult.OK;
                trdata tr = new trdata();
                tr.Values = CV;
                tr.Show();

                Visible = false; 
            }

这是Program.cs

static void Main()
    {
     Application.EnableVisualStyles();
     Application.SetCompatibleTextRenderingDefault(false);
     Form1 f1 = new Form1();
     Form2 s1 = new Form2();
     if (f1.ShowDialog() == DialogResult.OK)
      {
        Application.EnableVisualStyles();
        Application.SetCompatibleTextRenderingDefault(false);
        string result = s1.yourDesiredResult;
        Application.Run(s1);
       }
        else
        {
         Application.Exit();
        }
    }

页面截图：

C＃页面无法重新加载回上一页，并且datagridview数据丢失

0 个答案: