Question

我有很多这样的文件

BBG-06-0645-01B.txt 
BFDG_06-0219-01T.txt    
MFD-02-0047-011T.txt
BBTF_06-0649-01N.txt    
BFGD_02-2486-016J.txt

我正在尝试用下划线替换所有连字符，例如以下

BBG_06_0645_01B.txt 
BFDG_06_0219_01T.txt    
MFD_02_0047_011T.txt
BBTF_06_0649_01N.txt    
BFGD_02_2486_016J.txt

我尝试不使用sucecss使用以下内容

rename -nvs - _  *.txt
Using expression: sub { use feature ':5.18'; s/\Q${\"\-"}/_/ }
'BBG-06-0645-01B.txt' would be renamed to 'BBG_06-0645-01B.txt'
'BBTF_06-0649-01N.txt' would be renamed to 'BBTF_06_0649-01N.txt'
'BFDG_06-0219-01T.txt' would be renamed to 'BFDG_06_0219-01T.txt'
'BFGD_02-2486-016J.txt' would be renamed to 'BFGD_02_2486-016J.txt'
'MFD-02-0047-011T.txt' would be renamed to 'MFD_02-0047-011T.txt'

如果我也使用rename 's/\Q${\"\-"}/_/' *.txt，则不会更改-全部更改为_

Answer 1

在这里使用纯BASH替换。您能不能试一下。（仅适用于空转）

for file in *.txt
do
    echo "mv $file ${file//-/_}"
done

仅当您对命令（mv命令）感到满意之后，才会从上面的命令中删除echo。这只会首先打印语句。

这是输出mv BBG-06-0645-01B.txt BBG_06_0645_01B.txt

的示例

一旦您对以上使用以下结果感到满意。

for file in *.txt
do
     echo "File named $file is going to rename to ${file//-/_}"
     mv "$file" "${file//-/_}"
done

如果要显示状态，则已成功重命名或不使用的文件：

for file in *.txt
do
    echo "File named $file is going to rename to ${file//-/_}"
    if mv "$file" "${file//-/_}"
    then
         echo "File named $file is successfully renamed to ${file//-/_}"
    else
         echo "Please check seems file $file did not rename."
    fi
done

Answer 2

您可以像这样使用()：

rename

带有rename "s/-/_/g" *.txt标志的空运行：

-n

用for循环替换bash ：

rename -n "s/-/_/g" *.txt

以for file in *.txt; do mv "$file" "${file//-/_}" ; done而非echo进行空运行：

mv

如何替换多个文件名的一个字符串

2 个答案: