Question

我该如何编码以按以下顺序输出列：

unique_sis_group_id, unique_sis_user_id, unique_sis_school_id, mm_admin

我的代码：

$objs = @();
$output = Import-Csv -Path "c:\users\patrick\desktop\RelayFiles\RelayMemberships\file2concatenate.csv" | ForEach {
    $Object = New-Object PSObject -Property @{
        unique_sis_group_id  = [String]::Concat($_.unique_sis_group_id, $_.unique_sis_user_id)
        unique_sis_user_id = $_.unique_sis_school_id
        unique_sis_school_id = $_.mm_admin
        mm_admin = 0
    }
    $objs += $Object;
}
$objs
$objs | Export-Csv -NoTypeInformation c:\users\patrick\desktop\RelayFiles\RelayMemberships\memberships.csv

Answer 1

您将ForEach-Object分配给$output，但实际上没有任何内容输出。使用[PSCustomObject]更简单：

## Q:\Test\2019\01\25\SO_54373962.ps1
$CsvIn  = "c:\users\patrick\desktop\RelayFiles\RelayMemberships\file2concatenate.csv"
$CsvOut = "c:\users\patrick\desktop\RelayFiles\RelayMemberships\memberships.csv"
$output = Import-Csv -Path $CsvIn | ForEach-Object {
    [PSCustomObject]@{
         unique_sis_group_id  = [String]::Concat($_.unique_sis_group_id, $_.unique_sis_user_id)
         unique_sis_user_id   = $_.unique_sis_school_id
         unique_sis_school_id = $_.mm_admin
         mm_admin             = 0
    }
}
$output
$output | Export-Csv $CsvOut -NoTypeInformation

Answer 2

这已经解决了。有更好的方法吗？

rateStar.CssClass = "kv-fa";

PowerShell输出到CSV的顺序不正确

2 个答案: