这是目标代码:
public class DlpItem : IEqualityComparer<DlpItem>
{
public string Text { get; set; }
public int Id { get; set; }
public DlpItem(int pId)
{
Text = string.Empty;
Id = pId;
}
public override bool Equals(object obj)
{
return Id == (obj as DlpItem).Id;
}
public bool Equals(DlpItem a, DlpItem b)
{
return a.Id == b.Id;
}
public int GetHashCode(DlpItem item)
{
return Id.GetHashCode();
}
}
我有两个列表如下:
var list1 = new List<DlpItem>();
list1.Add(new DlpItem(1));
list1.Add(new DlpItem(2));
var list2 = new List<DlpItem>();
list2.Add(new DlpItem(1));
list2.Add(new DlpItem(2));
var delItems = list1.Except(list2).ToList<DlpItem>();
delItems总是包含两个项目。我在这里缺少什么?
编辑:代码现在实现IEquatable
public class DlpItem : IEqualityComparer<DlpItem>, IEquatable<DlpItem>
{
public string Text { get; set; }
public int Id { get; set; }
public override bool Equals(object obj)
{
return Id - (obj as DlpItem).Id == 0;
}
public bool Equals(DlpItem a, DlpItem b)
{
return a.Id == b.Id;
}
public bool Equals(DlpItem item)
{
return item != null && Id == item.Id;
}
public int GetHashCode(DlpItem item)
{
return Id.GetHashCode();
}
}
答案 0 :(得分:4)
在您的示例中,您实际上并未向list2
添加任何内容......这是一个非常简单的错误,但存在一个更重要的问题:
它必须是IEquatable<T>
而不是IEqualityComparer<T>
;另外,您可能希望确保哈希码无法更改;最简单的方法是将Id
设为只读:
public class DlpItem : IEquatable<DlpItem>
{
public string Text { get; set; }
private readonly int id;
public int Id { get { return id; } }
public DlpItem(int id)
{
Text = "";
this.id = id;
}
public override bool Equals(object obj)
{
return Equals(obj as DlpItem);
}
public bool Equals(DlpItem other)
{
return other != null && this.Id == other.Id;
}
public override int GetHashCode()
{
return Id.GetHashCode();
}
}