为什么调用Run()
阻止并且不返回?
正确打印以下输出,这很有意义。当我初始化大小为170的BatchBlock()
并创建200个volapoint对象时。但是为什么它不返回?
ConvertToVolaSurface
ConvertToVolaSurface
CalculateStrangles
CalculateStrangles
这是我正在使用的代码段
class Pipeline
{
public void Run()
{
// Grouping block - Collect vola points until vola surface is full
var batchBlock1 = new BatchBlock<VolaPoint>(170);
// Execution block - Convert vola points to surface
var transformBlock0 = new TransformBlock<VolaPoint[], VolaSurface>(x => this.ConvertToVolaSurface(x));
// Execution block - Calculate strangles
var transformBlock1 = new TransformBlock<VolaSurface, VolaSurface>(x => this.CalculateStrangles(x));
var linkOptions = new DataflowLinkOptions()
{
PropagateCompletion = true
};
batchBlock1.LinkTo(transformBlock0, linkOptions);
transformBlock0.LinkTo(transformBlock1, linkOptions);
for (int i = 0; i <= 200; i++)
{
batchBlock1.Post(new VolaPoint());
}
batchBlock1.Complete();
transformBlock1.Completion.Wait();
}
private VolaSurface ConvertToVolaSurface(VolaPoint[] volapoints)
{
Debug.WriteLine("ConvertToVolaSurface");
return new VolaSurface();
}
private VolaSurface CalculateStrangles(VolaSurface volaSurface)
{
Debug.WriteLine("CalculateStrangles");
return volaSurface;
}
}
答案 0 :(得分:1)
您的最后一块是TransformBlock
,变换块的输出缓冲区必须为Complete
为空。将最后一个块更改为ActionBlock
,然后await
完成,不阻塞调用线程。
public async Task Run()
{
// Grouping block - Collect vola points until vola surface is full
var batchBlock1 = new BatchBlock<VolaPoint>(170);
// Execution block - Convert vola points to surface
var transformBlock0 = new TransformBlock<VolaPoint[], VolaSurface>(x => this.ConvertToVolaSurface(x));
// Execution block - Calculate strangles
var actionBlock1 = new ActionBlock<VolaSurface>(x => this.CalculateStrangles(x));
var linkOptions = new DataflowLinkOptions()
{
PropagateCompletion = true
};
batchBlock1.LinkTo(transformBlock0, linkOptions);
transformBlock0.LinkTo(actionBlock1, linkOptions);
for (int i = 0; i <= 200; i++)
{
batchBlock1.Post(new VolaPoint());
}
batchBlock1.Complete();
await actionBlock1.Completion;
}
现在,如果CalculateStrangles(x)
返回的内容是,那么您需要将最后一个转换块链接到其他内容,否则您将永远无法完成。