Question

我有这个PHP，可以输出经理列表，并在其下方列出其员工和要求。

这现在很好用- 但是，我想将所有HTML存储在每个管理器的变量中，而不是在页面上输出。我该如何实现？

<?php 

while($row = $resultt->fetch_assoc())  {
    $arr = explode("@", $row['email'], 2);
    $first = $arr[0];
    $first = str_replace('.','-',$first);
    $email = $row['email'];
    $sql2 = "SELECT * FROM user WHERE manager_email LIKE '%".$email."%'";
    $resultt2 = $con->query($sql2);

    echo '<table class="'.$first.'">';

    $i++;

    while($row2 = $resultt2->fetch_assoc())  {

        echo '<tr><td>'.$row2['email'].':</td>';
        $sql3 = "SELECT * FROM requests WHERE submitted_by = '".$row2['email']."'";
        $resultt3 = $con->query($sql3);
        $count = 0;
        while($row3 = $resultt3->fetch_assoc())  {
            $count++;               
        }
        echo '<td>'.$count.'</td></tr>';
    }
    echo '</table>';
}

谢谢您的指导。

Answer 1

$output = '';
while($row = $resultt->fetch_assoc())  {
    $arr = explode("@", $row['email'], 2);
    $first = $arr[0];
    $first = str_replace('.','-',$first);
    $email = $row['email'];
    $sql2 = "SELECT * FROM user WHERE manager_email LIKE '%".$email."%'";
    $resultt2 = $con->query($sql2);

    $output .=  '<table class="'.$first.'">';

    $i++;

    while($row2 = $resultt2->fetch_assoc())  {

        $output .=  '<tr><td>'.$row2['email'].':</td>';
        $sql3 = "SELECT * FROM requests WHERE submitted_by = '".$row2['email']."'";
        $resultt3 = $con->query($sql3);
        $count = 0;
        while($row3 = $resultt3->fetch_assoc())  {
            $count++;               
        }
        $output .=  '<td>'.$count.'</td></tr>';
    }
    $output .=  '</table>';
}

echo $output;

所有输出现在存储在 $ output

中

将循环输出存储在变量中

1 个答案: