Question

因此，正如您在标题中看到的那样，我正在寻找如何查找所有tweet赞，然后在不丢失喜欢总结果的情况下向该查询添加喜欢的用户。

这是我的喜欢表。

SELECT COUNT(*) 
from likes INNER JOIN tweets ON likes.id_tweet = tweets.id 
GROUP BY likes.id_tweet;

+----------+---------+------+-----+---------+----------------+
| Field    | Type    | Null | Key | Default | Extra          |
+----------+---------+------+-----+---------+----------------+
| id       | int(11) | NO   | PRI | NULL    | auto_increment |
| id_user  | int(11) | NO   | MUL | NULL    |                |
| id_tweet | int(11) | NO   | MUL | NULL    |                |
+----------+---------+------+-----+---------+----------------+

运行此查询时，我可以得到所有赞：

SELECT COUNT(*) 
from likes INNER JOIN tweets ON likes.id_tweet = tweets.id 
GROUP BY likes.id_tweet;

赞：

+----------+
| COUNT(*) |
+----------+
|        1 |
|        4 |
|        1 |
|        1 |
|        2 |
|        1 |
|        1 |
|        1 |
|        1 |
|        2 |
|        1 |
|        1 |
|        3 |
|        1 |
|        1 |
|        1 |
|        1 |
|        1 |
|        1 |
|        1 |
|        3 |
|        2 |
|        1 |
|        1 |
|        2 |
|        1 |
|        3 |
|        1 |
|        1 |
|        1 |
|        3 |
|        3 |
|        2 |
+----------+

我很喜欢，但添加

 where likes.id_users = ...

我失去了一个用户喜欢的所有喜欢的东西，具体来说，我想恢复用户喜欢的所有推文的喜欢。

喜欢

+-----------+----+----------+-----------+------------+----------------------------------------------------------------------------------------------------------------------------------------------+--------+---------------------+
| all likes | id | id_reply | id_poster | id_retweet | text                                                                                                                                         | id_img | tweet_date          |
+-----------+----+----------+-----------+------------+----------------------------------------------------------------------------------------------------------------------------------------------+--------+---------------------+
|         50 |  2 |     NULL |      1714 |       NULL | Mon premier tweet                                                                                                                            |   NULL | 2019-01-23 14:25:24 |
|         43 | 35 |     NULL |      1752 |       NULL | Phasellus id sapien in sapien iaculis congue. Vivamus metus arcu, adipiscing molestie, hendrerit at, vulputate vitae, nisl. Aenean lectus. P |   NULL | 2018-04-29 00:00:00 |
|         22 | 50 |     NULL |      1908 |       NULL | In congue. Etiam justo. Etiam pretium iaculis justo. In hac habitasse platea dictumst. Etiam faucibus cursus urna. Ut tellus.                |   NULL | 2018-05-23 00:00:00 |
+-----------+----+----------+-----------+------------+----------------------------------------------------------------------------------------------------------------------------------------------+--------+---------------------+

谢谢

Answer 1

尝试一下：

SELECT COUNT(*), GROUP_CONCAT(likes.[id_user])
from likes INNER JOIN tweets ON likes.id_tweet = tweets.id 
GROUP BY likes.id_tweet;

从用户喜欢的推文中选择所有喜欢的内容

1 个答案: