给出日期列表:
a = ['2013-12-14', '2013-12-14', '2013-12-24', '2013-12-25', '2013-12-25', '2013-12-25']
我想通过计算每个日期的出现来计算熊猫时间序列:
2013-12-14 2
2013-12-15 0
2013-12-16 0
...
2013-12-24 1
2013-12-25 3
我该怎么做?
答案 0 :(得分:1)
您可以将to_datetime转换为datetime64,然后使用value_counts并重新采样:
/home/fabian/src/code-editor/app/Check.hs:11:1: error:
• Illegal polymorphic type: Lens' (String, String) a2
GHC doesn't yet support impredicative polymorphism
• In the type signature:
myField :: forall a_a5c6 a_a8tU.
Lens.Micro.Type.Lens (MyRecord a_a5c6) (MyRecord a_a8tU) (Lens' (String,
String) a_a5c6) (Lens' (String,
String) a_a8tU)
|
11 | makeLenses ''MyRecord