从Google Directions API获取最短路线

Question

我有一个问题。我想获得最短路线，并且我使用了这种算法。首先，我收集了所有路线的腿，然后选择了最短的腿。但是我不确定这是否是真的。这是找到最短路线的正确方法吗？因为在和，我手中没有最短的路线对象。我需要路由对象来获取其overview_polyline值。另外，如果我得到最短的路线，如何获得其距离？提前致谢！

DirectionsApi.getDirections(getGeoContext(), origin, destination)
                .mode(TravelMode.DRIVING)
                .alternatives(true)
                .origin("place_id:"+idPlaceOrigem)
                .destination("place_id:"+idPlaceDestino)
                .units(Unit.METRIC)
                .setCallback(new PendingResult.Callback<DirectionsResult>() {
                    @Override
                    public void onResult(DirectionsResult result) {
                        Set<Long> distances = new HashSet<>();
                        if (result != null && result.routes != null && result.routes.length > 0)
                            for (DirectionsRoute route : result.routes)
                                    for (DirectionsLeg leg : route.legs)
                                        if (leg.distance != null)
                                            distances.add(leg.distance.inMeters);

                        if (!distances.isEmpty()) {

                            ArrayList<Long> sortedList = new ArrayList(distances);

                            distance = min(sortedList);
                            despesaRequest.setKm_distancia(distance/1000);

                        }



                        runOnUiThread(new Runnable() {
                            @Override
                            public void run() {
                                updateDistance();
                                Singleton.getInstance().dismissLoading();
                            }
                        });
                    }

                    @Override
                    public void onFailure(Throwable e) {
                        Timber.e(e);
                        runOnUiThread(() -> {
                            Toast.makeText(LancamentoODIIActivity.this, "Não foi possível traçar a rota, por favor tenta novamente mais tarde.", Toast.LENGTH_SHORT).show();
                            Singleton.getInstance().dismissLoading();
                        });
                    }
                });
    }