我正在使用enumerate()
和python词典进行练习。当我不打印出枚举数据时,我能够从枚举数据创建字典。但是当我确实打印出枚举数据时,我将不再能够创建字典。为什么会这样?
当我不打印枚举数据时:
data = ['a','b','c','d']
enum_data = enumerate(data, 1)
data_dict = dict(enum_data)
print("Data Dict: ", data_dict)
print("Should be 'a': ", data_dict.get(1))
我的输出是
Data Dict: {1: 'a', 2: 'b', 3: 'c', 4: 'd'}
Should be 'a': a
但是当我不这样做时:
data = ['a','b','c','d']
enum_data = enumerate(data, 1)
for enum, point in enum_data:
print("Count: ", enum, " ", "Element: ", point)
data_dict = dict(enum_data)
print("Data Dict: ", data_dict)
print("Should be 'a': ", data_dict.get(1))
我得到:
Count: 1 Element: a
Count: 2 Element: b
Count: 3 Element: c
Count: 4 Element: d
Data Dict: {}
Should be 'a': None
答案 0 :(得分:2)
enumerate
返回一个迭代器。迭代器may only be iterated over once。
常见的解决方案是使用itertools.tee
返回任意数量的独立迭代器:
from itertools import tee
data = ['a','b','c','d']
enum_data1, enum_data2 = tee(enumerate(data, 1), 2)
for enum, point in enum_data1:
print("Count: ", enum, " ", "Element: ", point)
data_dict = dict(enum_data2)
print("Data Dict: ", data_dict) # {1: 'a', 2: 'b', 3: 'c', 4: 'd'}
print("Should be 'a': ", data_dict.get(1)) # a