Question

我有3张桌子 1.用户

name      surname  id     birthdate
Lowell    Bishop    1   1981-05-19
Rodney    Miller    2   1968-01-15
Binyamin  Boone     3   1991-12-21

2。友谊

userid1 userid2  timestamp
1       2      2018-12-03 20:11:03
1       3      2018-02-02 05:36:32
2       3      2018-01-16 02:50:08

3个赞

userid  postid   timestamp
1   4   2018-05-15 21:38:52
2   195 2018-11-17 09:28:43
3   252 2018-10-26 07:08:12

我有2个查询

/ 查询可获取在2018年3月拥有5个以上朋友的用户 /

SELECT  count(u1.id) as friends_count,
u1.id, u1.name,u1.surname FROM users u1
INNER JOIN friendships f ON f.userid1 = u1.id
INNER JOIN users u2 ON u2.id = f.userid2 
where f.timestamp >= '2025-03-01' and f.timestamp <= '2025-03-31' 
group by u1.id
having count(f.userid1) >= 5 
order by u1.id;

/ 查询可让用户在2018年3月获得5个以上的点赞 /

SELECT count(u1.id) as likes_count,u1.id, u1.name,u1.surname FROM users u1
INNER JOIN likes l ON u1.id = l.userid
where l.timestamp >= '2025-03-01' and l.timestamp <= '2025-03-31' 
group by u1.id
having count(u1.id) >= 5
order by u1.id;

如何将此2个查询相交为1个？我使用MySQL，所以相交给我一个错误。我正在尝试将此结果放入1个表中，如下所示：

friends_count   likes_count   id   name    surname
5               4             78   Joselyn   Lynn

Answer 1

您可以在下面尝试-使用子查询

select * from
(
SELECT  count(u1.id) as friends_count,
u1.id, u1.name,u1.surname FROM users u1
INNER JOIN friendships f ON f.userid1 = u1.id
INNER JOIN users u2 ON u2.id = f.userid2 
where f.timestamp >= '2025-03-01' and f.timestamp <= '2025-03-31' 
group by u1.id
having count(f.userid1) >= 5 
)A inner join 
(
SELECT count(u1.id) as likes_count,u1.id, u1.name,u1.surname FROM users u1
INNER JOIN likes l ON u1.id = l.userid
where l.timestamp >= '2025-03-01' and l.timestamp <= '2025-03-31' 
group by u1.id
having count(u1.id) >= 5
)B on A.ud=B.id

如何在MySQL中进行2个查询的相交

1 个答案: