Question

我的项目结构如下-

web.xml-

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns="http://xmlns.jcp.org/xml/ns/javaee" 
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd" 
id="WebApp_ID" version="4.0">
  <display-name>SpringWebApp</display-name>

    <servlet>
    <servlet-name>spring</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>spring</servlet-name>
    <url-pattern>/</url-pattern>
  </servlet-mapping>

  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
    <welcome-file>index.htm</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>default.html</welcome-file>
    <welcome-file>default.htm</welcome-file>
    <welcome-file>default.jsp</welcome-file>
  </welcome-file-list>
</web-app>

spring-servlet.xml-

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:p="http://www.springframework.org/schema/p"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/context
    http://www.springframework.org/schema/context/spring-context-3.0.xsd">

    <context:component-scan base-package="pac.test.*" />

    <bean
        class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix" value="/WEB-INF/views/" />
        <property name="suffix" value=".jsp" />
    </bean>
</beans>

控制器-

package pac.test;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.servlet.ModelAndView;

@Controller
public class LoginController {

    @RequestMapping(value="/login.htm")
public ModelAndView loginRequest() {

        ModelAndView mv = new ModelAndView("home");
        return mv;
    }
}

index.jsp

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
    <h2>
        <a href="login.htm">Login</a>
    </h2>
</body>
</html>

但是，在索引加载之后，当home.jsp明显存在于路径中时，单击超链接将生成404（找不到资源）。我根本无法理解我在这里做错了什么。我仔细检查了所有咒语等和路径。应该可以，但是不可以！

Spring甚至无法以某种方式到达Controller类。

Answer 1

尝试以下方法：

将@RequestMapping(value="/login.htm")更改为 @RequestMapping(value="/login")
将<a href="login.htm">Login</a>更改为 <a href="/SpringWebApp/login">Login</a>

您提供的链接似乎不正确，因此控制器未提取该链接。

Answer 2

@RequestMapping(value="/login.htm")
       public ModelAndView loginRequest() {
    ModelAndView mv = new ModelAndView("home");
    return mv;
}

从“ /login.htm”中删除“ .htm”

 @RequestMapping(value="/login")
       public ModelAndView loginRequest() {
    ModelAndView mv = new ModelAndView("home");
    return mv;
}

并像这样更正您的超链接

<h2>
    <a href="/login">Login</a>
</h2>

Answer 3

在您的web.xml中，您尚未定义spring-servlet.xml。因此像这样在spring-servlet.xml中定义web.xml。

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns="http://xmlns.jcp.org/xml/ns/javaee" 
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd" 
id="WebApp_ID" version="4.0">
  <display-name>SpringWebApp</display-name>

    <servlet>
    <servlet-name>spring</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>spring</servlet-name>
    <url-pattern>/</url-pattern>
  </servlet-mapping>

   <context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>WEB-INF/spring-servlet.xml</param-value>
   </context-param>

  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
    <welcome-file>index.htm</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>default.html</welcome-file>
    <welcome-file>default.htm</welcome-file>
    <welcome-file>default.jsp</welcome-file>
  </welcome-file-list>
</web-app>

现在像

那样写spring-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:p="http://www.springframework.org/schema/p"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/context
    http://www.springframework.org/schema/context/spring-context-3.0.xsd">

    <context:component-scan base-package="pac.test" />
    <mvc:annotation-driven/>

    <bean
        class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix" value="/WEB-INF/views/" />
        <property name="suffix" value=".jsp" />
    </bean>
</beans>

将您的控制器写为

@Controller
public class LoginController {

    @RequestMapping(value="/")
public ModelAndView loginRequest() {

        ModelAndView mv = new ModelAndView("home");
        return mv;
    }
}

在index.jsp页中，而不是像<a href="login.htm">Login</a>那样写<a href="/SpringWebApp/">Login</a>

SpringMVC无法到达控制器，每次都抛出404

3 个答案: