Question

我有一张桌子，在桌子的里面，我有一个文本框，用于查看页面。

现在的问题是，每当我更新特定的行或ID时，它就会更新所有内容。如何只更新特定的行或ID而又不更新所有内容？非常感谢你

这是我的控制器

 public function updateSchedule(Request $request, $id)
{
    $timein = $request->input('timeIn');
    $timeout = $request->input('timeOut');

    DB::table('schedules')
        ->update(['time_in' => $timein, 'time_out' => $timeout]);

    $notification = array(
        'message' => 'Employee Time Updated!',
        'alert-type' => 'success'
    );
    return redirect()->back()->with($notification, 'Employee Time Updated!');

}

这是我的观点

    {!! Form::open(['action' => ['Admin\EmployeeFilemController@updateSchedule', $employee->id], 'method' => 'POST']) !!}

        <div class="row">
            <div class="form-group col-md-12">

                <small>Employee No. and Name: </small><b><i> {{ $employee->employee_no }} : {{ $employee->last_name }}, {{ $employee->first_name }}</i></b>

                <input type="hidden" name="hidEmployeeno" value='<?php echo $employee->employee_no ?>'>
                <input type="hidden" name="hidEmployeeLast" value='<?php echo $employee->last_name ?>'>
                <input type="hidden" name="hidEmployeeFirst" value='<?php echo $employee->first_name ?>'>
                <hr>

            </div>

    </div>

        <table class="table">
            <thead>
              <tr>
                <th>DATE</th>
                <th>TIME IN</th>
                <th>LUNCH</th>
                <th>TIME OUT</th>
                <th>TOTAL HOURS</th>
                <th>STATUS</th>

              </tr>
            </thead>
            <tbody>

                    @foreach ($employeeSched as $setTime)
              <tr>

                 <td> {{Form::label('date_today', $setTime->date_today,['class'=>'form-control'])}}</td>
                 <td><input type="time" name="timeIn" class="form-control col-md-10" value='{{ $setTime->time_in }}'></td>
                 <td><p>12:00 PM - 1:00 PM</p></td>
                 <td><input type="time" name="timeOut" class="form-control col-md-10" value='{{ $setTime->time_out }}'></td>
                 <td>@php
                    $time1 = strtotime($setTime->time_in);
                    $time2 = strtotime($setTime->time_out);
                    $difference = round(abs($time2 - $time1) / 3600,2);
                    $total = $difference - 1;
                    echo '<b>' . $total . '</b>';
                 @endphp</td>


                <td>
                    @php
                    if ($total < 8) {
                        echo '<b>Late</b>';
                    } else if($total > 8) {
                        echo '<b>OT</b>';
                    } elseif ($total < 8.5 && $total == 8) {
                        echo '<b>In</b>';
                    }


                    @endphp
                </td>
              </tr>
              @endforeach



            </tbody>
    </table>
    {{Form::button('<i class="fa fa-clock">&nbsp;&nbsp;UPDATE TIME</i>',['type' => 'submit','class' => 'btn btn-info btn-sm',  'style'=>"display: inline-block;"])}}
    {{Form::hidden('_method', 'PUT')}}

    {!! Form::close() !!}

谢谢您的帮助，谢谢

Answer 1

由于您必须更改多个计划timeIn和timeOut，因此需要通过计划ID更新员工的计划时间。如下更新代码。我希望所提供的更改是不言自明的。

刀片（仅必需的部分）

<td><input type="time" name="schedules[{{ $setTime->id }}][timeIn]" class="form-control col-md-10" value='{{ $setTime->time_in }}'></td>
<td><input type="time" name="schedules[{{ $setTime->id }}][timeOut]" class="form-control col-md-10" value='{{ $setTime->time_out }}'></td>

注意：我假设$setTime->id是计划ID

控制器

public function updateSchedule(Request $request, $id)
{
    $schedules = $request->get('schedules');

    foreach ($schedules as $id => $schedule) {
        DB::table('schedules')
            ->where('id', $id)
            ->update([
                'time_in'  => $schedule['timeIn'], 
                'time_out' => $schedule['timeOut']
            ]);
    }

    $notification = array(
        'message' => 'Employee Time Updated!',
        'alert-type' => 'success'
    );

    return redirect()->back()->with($notification, 'Employee Time Updated!');
}

注意：即使未修改所有记录，此实现也会占用DB n（计划记录数）时间。

提示：您可以将旧值与可修改的值一起传递以进行比较，以进行比较，并仅对已修改的值执行更新查询。

Answer 2

您需要在查询中添加$ id，这就是它更新整行的原因：

DB::table('schedules')->where('id', $id)->update(['time_in' => $timein, 'time_out' => $timeout]);

此外，我将建议使用Eloquent。

Answer 3

您可以使用where子句（例如）按ID选择。

  DB::table('schedules')->where('id', $id)
        ->update(['time_in' => $timein, 'time_out' => $timeout]);

此外，如果一切正常，也可以尝试事务，或者在出现问题时捕获错误。

DB::beginTransaction();
try {
  DB::table('schedules')->where('id', $id)
        ->update(['time_in' => $timein, 'time_out' => $timeout]);

    DB::commit();

} catch (\Exception $e) {
    DB::rollback();
    print_r($e);die;

}

Answer 4

您也可以尝试这种方式。

DB::update('update schedules set time_in = "'.$timein.'", time_out = "'.$timeout.'" where id = "'.$id.'");

Answer 5

您没有告诉数据库您要更新的行。当您编写查询时，是“ update'table'set'col_name'='value'“;但是您需要告诉它要更新的ID。就像'where'id'= 12'。希望你能理解。：）

 public function updateSchedule(Request $request, $id){
  $timein = $request->input('timeIn');
  $timeout = $request->input('timeOut');
  DB::table('schedules')->where('id', $id)->update(['time_in' => $timein, 'time_out'=> $timeout]);
  $notification = array(
    'message' => 'Employee Time Updated!',
    'alert-type' => 'success'
);
return redirect()->back()->with($notification, 'Employee Time Updated!');
}

Laravel-仅更新所选数据

5 个答案: