点击后,wkwebview链接将无法打开

时间:2019-01-23 21:31:09

标签: ios objective-c wkwebview

我正在开发一个应用程序,该应用程序的代码继承自另一个开发人员,并具有可加载html文件的网络视图。

在html文件中是电话号码和Web链接。如果长按,则电话号码将打开,但是html链接未打开。

我希望它们能短按一下打开,但是短按不会发生任何事情。如果长按,则系统对话框会弹出“打开”选项,但按下“打开”则无济于事。

这是我的代码:

#import "IntroductionViewController.h"

@interface IntroductionViewController () <WKNavigationDelegate, WKUIDelegate>

@end

@implementation IntroductionViewController

@synthesize html_file_name;
@synthesize web_view;
@synthesize spinner;

- (void)viewDidLoad {
[super viewDidLoad];

self.navigationController.navigationBarHidden = NO;

[self setTitle:_title_string];

[self.web_view bringSubviewToFront:spinner];
[spinner setHidden:NO];
[spinner startAnimating];

NSURL *url = [[NSBundle mainBundle] URLForResource:html_file_name withExtension:@"html"];
[self.web_view loadRequest:[NSURLRequest requestWithURL:url]];
self.web_view.navigationDelegate = self;
self.web_view.UIDelegate = self;
}

- (void)webView:(WKWebView *)webView didFailProvisionalNavigation:(null_unspecified WKNavigation *)navigation withError:(NSError *)error {
[spinner setHidden:YES];
[spinner stopAnimating];
}

- (void)webView:(WKWebView *)webView didFinishNavigation:(null_unspecified WKNavigation *)navigation {
[spinner setHidden:YES];
[spinner stopAnimating];
}

- (BOOL)webView:(WKWebView *)webView shouldStartLoadWithRequest (NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType {
NSLog(@"called here");
if (navigationType == UIWebViewNavigationTypeLinkClicked ) {
    UIApplication *application = [UIApplication sharedApplication];
    [application openURL:[request URL] options:@{} completionHandler:nil];
    return YES;
}
return YES;
}

@end

从未调用过“ shouldStartLoadWithRequest”。

2 个答案:

答案 0 :(得分:1)

我设法通过删除代码的“ shouldStartLoadWithRequest”部分并添加以下部分来使此工作正常进行:

- (void)webView:(WKWebView *)webView decidePolicyForNavigationAction:(nonnull WKNavigationAction *)navigationAction decisionHandler:(nonnull void (^)(WKNavigationActionPolicy))decisionHandler {
if (navigationAction.navigationType == WKNavigationTypeLinkActivated) {
    if (navigationAction.request.URL) {
        NSLog(@"%@", navigationAction.request.URL.host);
        if (![navigationAction.request.URL.resourceSpecifier containsString:@"ex path"]) {
            if ([[UIApplication sharedApplication] canOpenURL:navigationAction.request.URL]) {
                UIApplication *application = [UIApplication sharedApplication];
                [application openURL:navigationAction.request.URL options:@{} completionHandler:nil];
                decisionHandler(WKNavigationActionPolicyCancel);
            }
        } else {
            decisionHandler(WKNavigationActionPolicyAllow);
        }
    }
} else {
    decisionHandler(WKNavigationActionPolicyAllow);
}
}

现在,所有链接都将按预期方式打开,在单独的(新)窗口中显示Web链接,并且只需短按即可。

答案 1 :(得分:0)

短按下面的代码打开长点击事件...

func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: ((WKNavigationActionPolicy) -> Void)) {

        switch navigationAction.navigationType {
        case .linkActivated:
            UIApplication.shared.openURL(navigationAction.request.url!)
            decisionHandler(.cancel)
            return
        default:
            break
        }
        decisionHandler(.allow)
    }