我需要在2列中组合多个值，以在同一行中显示enter code >here，并按一个通用值（即电子邮件enter code >here地址，ID）汇总
我已经能够使用“ FOR XML PATH（''），1,1''）”的一列完成此操作。但是，当我尝试在另一列上使用完全相同的语法和命令时，它不会合并。因此，我得到列A =单个值，并且列B = B1，B2，B3 ..
Declare @StartDate DateTime, @EndDate DateTime
set @StartDate = Getdate() - 1
set @EndDate = GetDate()
SELECT DISTINCT
pat.email as ADDR,
pat.fname as INS1,
STUFF((SELECT ', ' + right(rx.script_no,4)
FROM cprx rx
WHERE disp.rx_id = rx.rx_id
and disp.rxdisp_id = rx.last_rxdisp_id
and (rx.refills_left is not NULL AND Not(rx.refills_left between -0.1
and 0.1))
and len(rx.script_no) = 7
FOR XML PATH('')),1,1,'')[RxRight4],
STUFF((SELECT ', ' + left(disp.disp_drug_name,2)
FROM cprx_disp disp
WHERE om.order_id = disp.order_id
FOR XML PATH('')),1,1,'') [DrugLeft2]
FROM csom om (nolock)
join cprx_disp disp (nolock) on om.order_id = disp.order_id
join cprx rx (nolock) on disp.rx_id = rx.rx_id and (rx.refills_left
is not NULL AND Not(rx.refills_left between -0.1 and 0.1))
join cppat pat (nolock) on rx.pat_id = pat.pat_id
join cppat_ins patins (nolock) on pat.pat_id = patins.pat_id
WHERE (pat.email <> 'none' and pat.email <> ' ' and pat.email IS NOT
NULL)
AND ISNULL(pat.status_cn, 0) IN (0, 1, 2)
AND ISNULL(pat.pat_status_cn, 1) IN (0, 1)
and ((dispense_date + (disp_days_supply*.75)) BETWEEN @StartDate and
@Enddate
and (rx.refills_left is not NULL AND Not(rx.refills_left between -0.1
and 0.1))
AND rx.store_id in (1)
AND IsNull(rx.manual_add_yn,0) = 0
AND rx.script_status_cn = 0
AND disp.rxdisp_id = rx.last_rxdisp_id)
Group by Pat.email, Pat.fname, disp.rx_id,disp.rxdisp_id, om.order_id
Order by INS1,ADDR
我加入了我的联接，以防万一可能是我的问题。因此，我需要将[RxRight4]值全部放在一行中，并按INS1和ADDR>值汇总。它对[DrugLeft2]很好，但对[RxRight4]不好。
例如，我需要结果是这样的：
ADDR INS1 RxRight4 DrugLeft2
Joe@gmailcom ABC Group 1234, 4321, 3124 AB, BC, CD
But, what I get is this:
ADDR INS1 RxRight4 DrugLeft2
Joe@gmail.com ABC Group 1234 AB, BC, CD
Joe@gmail.com ABC Group 4321 AB, BC, CD
Joe@gmail.com ABC Group 3124 AB, BC, CD
答案 0 :(得分：0)
在主SELECT表达式中，您有两个带有嵌套SELECT表达式的STUFF函数。在FROM部分中的STUFFs SELECTs中声明的表相对于JOIN中声明的表是独立的。当您在STUFF函数中编写“ FROM cprx rx”和“ FROM cprx_disp disp”时，它们是关于“ JOIN cprx rx”和“ JOIN cprx_disp disp”声明的不同表。
[DrugLeft2]是正确的，因为具有“ WHERE om.order_id = disp.order_id”，但是 [RxRight4]没有直接连接到om表。
下面是您的代码，仅为便于阅读而分解：
DECLARE @StartDate DateTime, @EndDate DateTime;
SET @StartDate = Getdate() - 1;
SET @EndDate = GetDate();
SELECT DISTINCT
pat.email as ADDR,
pat.fname as INS1,
STUFF((SELECT ', ' + right(rx.script_no,4)
FROM cprx rx
WHERE disp.rx_id = rx.rx_id
AND disp.rxdisp_id = rx.last_rxdisp_id
AND (rx.refills_left IS NOT NULL AND NOT(rx.refills_left BETWEEN -0.1 AND 0.1))
AND LEN(rx.script_no) = 7
FOR XML PATH('')),1,1,'') [RxRight4],
STUFF((SELECT ', ' + left(disp.disp_drug_name,2)
FROM cprx_disp disp
WHERE om.order_id = disp.order_id
FOR XML PATH('')),1,1,'') [DrugLeft2]
FROM csom om (nolock)
JOIN cprx_disp disp (nolock) on om.order_id = disp.order_id
JOIN cprx rx (nolock) on disp.rx_id = rx.rx_id AND (rx.refills_left IS NOT NULL AND NOT(rx.refills_left between -0.1 and 0.1))
JOIN cppat pat (nolock) on rx.pat_id = pat.pat_id
JOIN cppat_ins patins (nolock) on pat.pat_id = patins.pat_id
WHERE (pat.email <> 'none' AND pat.email <> ' ' AND pat.email IS NOT NULL)
AND ISNULL(pat.status_cn, 0) IN (0, 1, 2)
AND ISNULL(pat.pat_status_cn, 1) IN (0, 1)
AND ((dispense_date + (disp_days_supply*.75)) BETWEEN @StartDate AND @Enddate
AND (rx.refills_left IS NOT NULL AND NOT(rx.refills_left between -0.1 AND 0.1))
AND rx.store_id in (1) AND ISNULL(rx.manual_add_yn,0) = 0 AND rx.script_status_cn = 0 AND disp.rxdisp_id = rx.last_rxdisp_id)
GROUP BY Pat.email, Pat.fname, disp.rx_id,disp.rxdisp_id, om.order_id
ORDER BY INS1,ADDR
答案 1 :(得分：0)
马克，我使用@table变量模拟了您的数据，请注意，我不确定您真正拥有的数据是什么，但我相信这足以解决您的查询。
首先，我将STUFF函数中的嵌套SELECT与主SELECT中的JOIN分开。现在，此嵌套查询将在每个结果行中分别执行。注意，主JOIN中的表具有新的别名disp2和rx2。
第二，在[RxRight4]列的STUFF函数中的嵌套SELECT中，我添加了“ JOIN @cprx_disp disp ON om.order_id = disp.order_id”，通过独立于主SELECT中的disp2表的disp表将om表与cprx rx连接起来
第三，我评论了一些WHERE子句，但我不知道哪个数据可以满足它：
-- AND LEN(rx.script_no) = 7
--AND ((dispense_date + (disp_days_supply*.75)) BETWEEN @StartDate AND @Enddate
-- AND (rx.refills_left IS NOT NULL AND NOT(rx.refills_left between -0.1 AND 0.1))
-- AND rx.store_id in (1) AND ISNULL(rx.manual_add_yn,0) = 0 AND rx.script_status_cn = 0 AND disp.rxdisp_id = rx.last_rxdisp_id)
示例代码现在显示为：
DECLARE @cppat TABLE (id int, pat_id int, email varchar(20), fname varchar(20), status_cn int, pat_status_cn int );
DECLARE @cppat_ins TABLE (id int, pat_id int, status_cn int);
DECLARE @cprx TABLE (id int,rx_id int, last_rxdisp_id int,pat_id int, script_no varchar(10), refills_left int);
DECLARE @cprx_disp TABLE (id int, rx_id int, order_id int, rxdisp_id int, disp_drug_name varchar(20));
DECLARE @csom TABLE (order_id int);
INSERT INTO @cppat (id, pat_id, email, fname, status_cn, pat_status_cn)
VALUES
(1,1,'Joe.gmail.com','ABC GROUP',1,1);
INSERT INTO @cppat_ins (id, pat_id, status_cn)
VALUES
(1,1,1);
INSERT INTO @cprx (id, rx_id, last_rxdisp_id, pat_id, script_no, refills_left)
VALUES
(1,1,1,1,'1234',1)
,(1,2,1,1,'4321',1)
,(1,3,1,1,'3124',1);
INSERT INTO @cprx_disp (id, rx_id, order_id, rxdisp_id, disp_drug_name)
VALUES
(1,1,1,1,'AB')
,(1,2,1,1,'BC')
,(1,3,1,1,'CD');
INSERT INTO @csom (order_id)
VALUES
(1);
DECLARE @StartDate DateTime, @EndDate DateTime;
SET @StartDate = GETDATE() - 1;
SET @EndDate = GETDATE();
SELECT DISTINCT
pat.email as ADDR,
pat.fname as INS1,
STUFF((SELECT ', ' + right(rx.script_no,4)
FROM @cprx rx
JOIN @cprx_disp disp ON om.order_id = disp.order_id
WHERE disp.rx_id = rx.rx_id
AND disp.rxdisp_id = rx.last_rxdisp_id
AND (rx.refills_left IS NOT NULL AND NOT(rx.refills_left BETWEEN -0.1 AND 0.1))
--AND LEN(rx.script_no) = 7
FOR XML PATH('')),1,1,'') [RxRight4],
STUFF((SELECT ', ' + left(disp.disp_drug_name,2)
FROM @cprx_disp disp
WHERE om.order_id = disp.order_id
FOR XML PATH('')),1,1,'') [DrugLeft2]
FROM @csom om
JOIN @cprx_disp disp2 ON om.order_id = disp2.order_id
JOIN @cprx rx2 ON disp2.rx_id = rx2.rx_id AND (rx2.refills_left IS NOT NULL AND NOT(rx2.refills_left between -0.1 and 0.1))
JOIN @cppat pat ON rx2.pat_id = pat.pat_id
JOIN @cppat_ins patins ON pat.pat_id = patins.pat_id
WHERE (pat.email <> 'none' AND pat.email <> ' ' AND pat.email IS NOT NULL)
AND ISNULL(pat.status_cn, 0) IN (0, 1, 2)
AND ISNULL(pat.pat_status_cn, 1) IN (0, 1)
--AND ((dispense_date + (disp_days_supply*.75)) BETWEEN @StartDate AND @Enddate
-- AND (rx.refills_left IS NOT NULL AND NOT(rx.refills_left between -0.1 AND 0.1))
-- AND rx.store_id in (1) AND ISNULL(rx.manual_add_yn,0) = 0 AND rx.script_status_cn = 0 AND disp.rxdisp_id = rx.last_rxdisp_id)
GROUP BY Pat.email, Pat.fname, disp2.rx_id,disp2.rxdisp_id, om.order_id
ORDER BY INS1,ADDR
，查询结果为：
ADDR INS1 RxRight4 DrugLeft2
-------------------- -------------------- ------------------- --------------------
Joe.gmail.com ABC GROUP 1234, 4321, 3124 AB, BC, CD