Question

在运行程序并提供用户输入时，它仅执行代码中的最后一个功能。我知道代码有什么问题，我用不同的参数重新定义了相同的函数。但是，我不知道如何更改它，以便代码将运行与用户输入匹配的功能。这是我为程序编写的代码。

this.mixer = new THREE.AnimationMixer(this.box);
this.animation = this.mixer.clipAction(this.box.geometry.animations[0]);
this.animation.setDuration(1.5);
this.animation.setLoop(THREE.LoopOnce, 1);

this.mixer.addEventListener( 'finished', function() {
    this.animation.stop();
    // HOW animation-fill-mode: forwards ?
});

Answer 1

您需要给每个方程式函数一个唯一的名称。这将允许您构建一个将标识符映射到每个标识符的字典。另外，在调用所选函数之前，您需要获取一个参数值以传递所选函数。

这是做所有这些事情的一个例子：

import math
from math import pi


def equation1(Lift):
  d = float(input("Input d value: "))
  v = float(input("Input v value: "))
  A = float(input("Input A value: "))
  CL = float(input("Input CL value: "))

  Lift = .5 * d * (v ** 2) * A * CL

  a = ["Lift = ", Lift, "Newtons"]
  for i in range (3):
    print(a[i], end =" ")

def equation2(VCylinder):
  r = float(input("Input r value: "))
  h = float(input("Input h value: "))

  VCylinder = pi * (r ** 2) * h

  a = ["Volume of Cylinder =", VCylinder, "m³ (meters³)"]
  for i in range(3):
    print(a[i], end =" ")

def equation3(Exponentdx):
  n = int(input("Input n value: "))

  u = n
  v = n - 1

  a = ["dx =", u,"x","**", v, " "]
  for i in range(5):
    print(a[i], end =" ")

# Build dictionary mapping an equation identifer to equation functions.
equations = {
    '1': equation1,
    '2': equation2,
    '3': equation3,
}

def Main():
  print("Currently only compatible with base metric units (meters, kilograms, etc.)")
  eq_id = input("Enter desired equation function (1, 2, or 3): ")
  eq_arg = float(input("Enter value of argument to pass equation function: "))
  equations[eq_id](eq_arg)  # Call selected equation with argument.

Main()

我无法让我的代码执行用户输入所选择的功能

1 个答案: