preg_replace如果结果替换或不替换。仅显示替换的文本，否则为空白

Question

我想获取preg_replace如果替换，则显示结果，否则为空白

<?php
 $text = "text4 text1 text2 text3";
 $replace = [
 '/\btext1\b/'         => 'replace1', //replace case sensitive
 '/\btext2\b/i'         => 'replace2', //non-sensitive
 '/\b(text3|text4)\b/i' => 'replace3', //replace both text3 and text4
 ];
$result = preg_replace(array_keys($replace), $replace, $text);

echo $result;

  

结果= replace3 replace1 replace2 replace3

还有

<?php
 $text = "text4x text1x text2x text3x";
 $replace = [
 '/\btext1\b/'         => 'replace1', //replace case sensitive
 '/\btext2\b/i'         => 'replace2', //non-sensitive
 '/\b(text3|text4)\b/i' => 'replace3', //replace both text3 and text4
 ];
$result = preg_replace(array_keys($replace), $replace, $text);

echo $result;

  

结果= text4x text1x text2x text3x

如果不替换任何内容，则显示原始$ text，如果任何单词不替换，我想在此处显示空白结果

Answer 1

您可以使用strcmp比较字符串。

strcmp（$ text，$ result）; //如果字符串相同则返回0

$compare = strcmp($text,$result);
if($compare == 0){ echo $text;  }
else { echo 'Result not found'; }