Question

是否有一种方法或库可以将JSON schema文件转换为Qt ui形式？很像JSON Editor可以转换JSON-> HTML形式。我在网上没有运气。

非常感谢。

Answer 1

如果您知道可以从JSON文件中获取的信息类型，则可以编写一个小的Delegate来正确绘制模型并使用JSONListModel。

例如：

{ "store": {
    "book": [
      { "category": "reference",
        "author": "Nigel Rees",
        "title": "Sayings of the Century",
        "price": 8.95
      },
      { "category": "fiction",
        "author": "Evelyn Waugh",
        "title": "Sword of Honour",
        "price": 12.99
      },
      { "category": "fiction",
        "author": "Herman Melville",
        "title": "Moby Dick",
        "isbn": "0-553-21311-3",
        "price": 8.99
      },
      { "category": "fiction",
        "author": "J. R. R. Tolkien",
        "title": "The Lord of the Rings",
        "isbn": "0-395-19395-8",
        "price": 22.99
      }
    ],
    "bicycle": {
        "color": "red",
        "price": 19.95
    }
  }
}

可以替换为：

    JSONListModel {
        id: jsonModel1
        source: "jsonData.txt"
        // All books in the store object
        query: "$.store.book[*]"
    }

    JSONListModel {
        id: jsonModel2
        source: "jsonData.txt"
        // Books less than $10
        query: "$..book[?(@.price<10)]"
    }

    JSONListModel {
        id: jsonModel3
        json: '[ \  
            {"label": "Answer", "value": "42"}, \
            {"label": "Pastis", "value": "51"}, \
            {"label": "Alsace", "value": "67"}, \
            {"label": "Alsace", "value": "68"} \
        ]'
        // Labels starting with 'A'
        query: "$[?(@.label.charAt(0)==='A')]"
    }

在您的QML文件中，您可以执行以下操作：

    ListView {
        model: jsonModel1.model

        delegate: Component {
            Text {
                // Can be any of the JSON properties: model.author, model.price, etc.
                text: model.title
            }
        }

该项目位于以下位置：https://github.com/kromain/qml-utils

编译JSON以创建Qt ui表单

1 个答案: