我正在使用服务器上的asp.net core 2.2和ef core 2.2以及客户端的Angular 7开发应用程序。我无法弄清楚:
我有以下(简化的)模型:
public abstract class LegalEntity
{
public int Id { get; set; }
public int Name { get; set; }
public Address FiscalAddress { get; set; }
}
public class Organisation : LegalEntity
{
public Organisation(){}
public Organisation(LegalEntityType legalEntityType, string name, Address fiscalAddress)
{
LegalEntityType = legalEntityType;
Name = name;
}
public LegalEntityType LegalEntityType { get; set; }
}
public class LegalEntityType
{
public int Id { get; set; }
public int Name { get; set; }
public LegalEntityType(){}
public LegalEntityType(string name)
{
Name = name;
}
}
public class Person : LegalEntity
{
public Gender Gender { get; set; }
public string FirstName { get; set; }
public string LastName { get; set; }
public override string Name => string.Format("{0} {1}", FirstName, LastName);
}
public class Gender
{
public int Id { get; set; }
public int Name { get; set; }
}
public class Customer
{
public int Id { get; set; }
public Customer(){}
public Customer(LegalEntity legalEntity)
{
LegalEntity = legalEntity;
}
public LegalEntity LegalEntity { get; set; }
}
当我通过API将客户实体返回给客户时,有时LegalEntity是一个组织,有时是一个人。在返回哪种类型(组织或个人)之后,我希望将属性LegalEntityType(对于组织而言)或属性Gender(对于Person而言)呈现为JSON代码。这是我的第一个问题,以下内容使它们都为空:
.Include(o => o.Customer).ThenInclude(o => o.LegalEntity)
,因为这不会加载仅在继承实体中存在的导航属性。这是
情况下JSON字符串的摘录人员:
...
"customer": {
"legalEntity": {
"gender": null,
"firstName": "Denis",
"lastName": "Testmann",
"name": "Denis Testmann",
"id": 9
},
...
组织:
...
"customer": {
"legalEntity": {
"legalEntityType": null,
"name": "Companyname GmbH",
"id": 6
},
...
应显示以下内容:
人员:
...
"customer": {
"Person": {
"gender": null,
"firstName": "Denis",
"lastName": "Testmann",
"name": "Denis Testmann",
"id": 9
},
...
组织:
...
"customer": {
"Organisation": {
"legalEntityType": null,
"name": "Companyname GmbH",
"id": 6
},
...
要指出的是:客户可能是个人或组织,实体(组织和个人)都继承自LegalEntity,因此客户财产“ LegalEntity”有时是个人,有时是组织。当我渲染JSON时,必须保持特定的类型。
希望我已经足够清楚了-请原谅我这么久,我想确定问题已得到理解。
答案 0 :(得分:0)
新答案
我通过dotnet core 2.1通过dotnet new console
整理了以下Program.cs:
using System;
using System.Collections.Generic;
using Newtonsoft.Json;
class Program
{
static void Main(string[] args)
{
var list = new List<Customer>();
list.Add(new Customer(new Person { Gender = new Gender{ Name = "Male"}}));
list.Add(new Customer(new Organisation { LegalEntityType = new LegalEntityType{ Name = "GmbH"}}));
Console.WriteLine(JsonConvert.SerializeObject(list, Newtonsoft.Json.Formatting.Indented));
}
}
public abstract class LegalEntity
{
public int Id { get; set; }
public virtual string Name { get; set; }
public Address FiscalAddress { get; set; }
}
public class Organisation : LegalEntity
{
public Organisation(){}
public Organisation(LegalEntityType legalEntityType, string name, Address fiscalAddress)
{
LegalEntityType = legalEntityType;
Name = name;
}
public LegalEntityType LegalEntityType { get; set; }
}
public class LegalEntityType
{
public int Id { get; set; }
public string Name { get; set; }
public LegalEntityType(){}
public LegalEntityType(string name)
{
Name = name;
}
}
public class Person : LegalEntity
{
public Gender Gender { get; set; }
public string FirstName { get; set; }
public string LastName { get; set; }
public override string Name => string.Format("{0} {1}", FirstName, LastName);
}
public class Gender
{
public int Id { get; set; }
public string Name { get; set; }
}
public class Customer
{
public int Id { get; set; }
public Customer(){}
public Customer(LegalEntity legalEntity)
{
LegalEntity = legalEntity;
}
public LegalEntity LegalEntity { get; set; }
}
public class Address
{
public int Id { get; set; }
public string Line1 { get; set; }
public string Line2 { get; set; }
}
输出显示如下:
[
{
"Id": 0,
"LegalEntity": {
"Gender": {
"Id": 0,
"Name": "Male"
},
"FirstName": null,
"LastName": null,
"Name": " ",
"Id": 0,
"FiscalAddress": null
}
},
{
"Id": 0,
"LegalEntity": {
"LegalEntityType": {
"Id": 0,
"Name": "GmbH"
},
"Id": 0,
"Name": null,
"FiscalAddress": null
}
}
]
这看起来还好吗?也许请检查您的API端点绑定程序正在使用哪些序列化程序设置。
旧答案
如果LegalEntity是数据库中的真实表,则您应该可以使用:
[ForeignKey("LegalEntity")]
public int LegalEntityId { get; set; }
在您的Customer
定义中。
您还需要设置密钥:
public abstract class LegalEntity
{
[Key]
public int Id { get; set; }
public int Name { get; set; }
public Address FiscalAddress { get; set; }
}
如果LegalEntity不是真实的表格,则为“人员/组织”添加单独的导航
答案 1 :(得分:0)
好-找到解决方案了!
在服务器端,您必须使用
序列化JSON内容SerializerSettings.TypeNameHandling = TypeNameHandling.Auto
您应该在Startup.cs文件中做什么:
services.AddJsonOptions(opt =>
{
opt.SerializerSettings.ReferenceLoopHandling =
Newtonsoft.Json.ReferenceLoopHandling.Ignore;
opt.SerializerSettings.TypeNameHandling = TypeNameHandling.Auto;
})
,在客户端,您可以使用类转换器(https://github.com/typestack/class-transformer)。
在我的示例中,客户类别-LegalEntity可能是Person或Organization类型的外观如下:
public class Customer
{
public int Id { get; set; }
@Type( () => Object, {
discriminator: {
property: '$type',
subTypes: [
{value: Person, name: 'Your.Name.Space.Person, YourApp.Name'},
{value: Organisation, name: 'Your.Name.Space.Organisation, YourApp.Name'},
],
},
})
public LegalEntity LegalEntity { get; set; }
}
然后从像这样的普通javascript对象构建customer类的实例:
import { plainToClass } from 'class-transformer';
export class SomeClassInYourAngularApp implements OnInit {
customerList: Customer[];
ngOnInit() {
this.customerList = new Array<Customer>();
let u: any;
// lets get the plain js object form somewhere, ex. from a resolver
this.route.data.subscribe(data => {
u = data['customerList'].result;
});
u = plainToClass(Customer, u);
Object.assign(this.customerList, u);
}
就是这样!