Question

因此，我在这里按照教程进行逐步操作，无法摆脱此异常。我的连接字符串看起来不错。本教程中没有发生这种情况，所以我不知道出了什么问题。它使我进入这一行Employee employee = employeeContext.Employees.Single（emp => emp.EmployeeId == id）;

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.Mvc;
using ATSTest.Models;


namespace ATSTest.Controllers
{
    public class EmployeeController : Controller
    {
        // GET: Employee
        public ActionResult Details(int id)
        {
            EmployeeContext employeeContext = new EmployeeContext();
            Employee employee = employeeContext.Employees.Single(emp => emp.EmployeeId == id);

            return View(employee);
        }
    }
}

这是我的班级

using System.ComponentModel.DataAnnotations;
using System.ComponentModel.DataAnnotations.Schema;
using System.Linq;
using System.Web;

namespace ATSTest.Models
{   
    [Table("Employees")]
    public class Employee
    {

        public int EmployeeId { get; set; }
        public string FirstName { get; set; }
        public string LastName { get; set; }
        public string HiredDate { get; set; }
    }
}

连接字符串

<connectionStrings>
    <add name ="EmployeeContext" connectionString="Data Source=(LocalDb)\MSSQLLocalDB;Initial Catalog=AssetTracking;Integrated Security=True" providerName="System.Data.SqlClient" />

  </connectionStrings>

EmployeeContext类

using System;
using System.Collections.Generic;
using System.Data.Entity;
using System.Linq;
using System.Web;

namespace ATSTest.Models

    {
        public class EmployeeContext : DbContext
        {
            public DbSet<Employee> Employees { get; set; }
        }
    }

Answer 1

您的问题的答案是您没有使用连接字符串。

您将必须传递连接字符串名称，如下例所示。

public class EmployeeContext : DbContext
{
    public EmployeeContext()
        : base("EmployeeContext")
    {

    }

    // DbSet's here
    publlic DbSet<Employee> Employees { get; set; }
}

System.Core.dll中发生类型为'System.invalidOperationException'的异常，但未在用户代码中处理

1 个答案: