Question

HTTP请求正文示例

<Name>Cátia</Name>

HTTP响应正文示例

<Name>C�tia</Name>

这是请求类

@JacksonXmlRootElement(localName = "Root")
public class Request {

    @JacksonXmlProperty(isAttribute = true, localName = "Id")
    private String id;

    @JacksonXmlProperty(isAttribute = true, localName = "Name")
    private String name;
}

这是HTTP请求

HttpHeaders httpHeaders = new HttpHeaders();
httpHeaders.add(HttpHeaders.CONTENT_TYPE, "application/xml;charset=UTF-8");

HttpEntity<> httpEntity = new HttpEntity<>(request, httpHeaders);

responseEntity = restTemplate
    .exchange("URL", HttpMethod.POST, httpEntity, Response.class);

这是Response类

@JsonDeserialize(using = ResponseDeserializer.class)
public class Response {

    @JacksonXmlProperty(localName = "NAME")
    public String name;
}

这是ResponseDeserializer类

public class ResponseDeserializer extends JsonDeserializer<Response> {
    @Override
    public Response deserialize(JsonParser p, DeserializationContext ctxt) throws IOException {

        ObjectCodec objectCodec = p.getCodec();
        JsonNode jsonNode = objectCodec.readTree(p);

        return JsonUtils.getObjectMapper().readValue(JsonUtils.getObjectMapper().writeValueAsString(jsonNode),
            Response.class);
    }
}

这是个例外

JsonNode jsonNode = objectCodec.readTree（p）;

readTree方法抛出'com.fasterxml.jackson.core.JsonParseException'   例外。无效的UTF-8中间字节0x74（在char＃2480，字节＃1371处）

Answer 1

通过添加isUTF8Support = true作为HTTP URL参数来解决。

杰克逊解串器使用无效的UTF-8中间字节抛出JsonParseException，而反串器字符串带有重音符号

1 个答案: