Question

我想获得scores对象的最高价值。

我有一个全局对象“ implements”：

[
  {
    "id": 5,
    "project": 'name project',
    "scores": [
      {
        "id": 7,
        "user_id": 30,
        "implementation_id": 5,
        "score": "12.00",
        "comment": "C'est de la merde, ça vient d’Anthony."
      },
      {
        "id": 10,
        "user_id": 31,
        "implementation_id": 5,
        "score": "15.00",
        "comment": "Super"
      }
    ]
  },
  {
    "id": 6,
    "project": 'name project',
    "scores": [
      {
        "id": 8,
        "user_id": 30,
        "implementation_id": 6,
        "score": "20.00",
        "comment": "Super!"
      },
      {
        "id": 11,
        "user_id": 31,
        "implementation_id": 6,
        "score": "12.00",
        "comment": "Super"
      },
      {
        "id": 15,
        "user_id": 36,
        "implementation_id": 6,
        "score": "10.00",
        "comment": "Super"
      }
    ]
  }
]

例如，在上述对象中，对象1有2分，而对象2有3分。

我想要两者的最大价值。如果我们添加第三个对象，并且得到5分，我想得到5分。

如何使用javascript函数做到这一点？

谢谢

Answer 1

最简单的方法是创建一个虚拟值并计算计数。然后对其进行排序。

const scoresList = [
  {
    "id": 5,
    "project": 'name project',
    "scores": [
      {
        "id": 7,
        "user_id": 30,
        "implementation_id": 5,
        "score": "12.00",
        "comment": "C'est de la merde, ça vient d’Anthony."
      },
      {
        "id": 10,
        "user_id": 31,
        "implementation_id": 5,
        "score": "15.00",
        "comment": "Super"
      }
    ]
  },
  {
    "id": 6,
    "project": 'name project',
    "scores": [
      {
        "id": 8,
        "user_id": 30,
        "implementation_id": 6,
        "score": "20.00",
        "comment": "Super!"
      },
      {
        "id": 11,
        "user_id": 31,
        "implementation_id": 6,
        "score": "12.00",
        "comment": "Super"
      },
      {
        "id": 15,
        "user_id": 36,
        "implementation_id": 6,
        "score": "10.00",
        "comment": "Super"
      }
    ]
  }
];

for(var i = 0; i < scoresList.length; i++){
   //create a dummy variable scoreCount
    scoresList[i].scoreCount = 0;
    if(scoresList[i].scores){
              scoresList[i].scoreCount = scoresList[i].scores.length;
    }

}
scoresList.sort(function(a, b){ 
    return b.scoreCount - a.scoreCount
});

console.log(scoresList[0]); //This will give you the score with highest count

Answer 2

我个人认为，这些任务可以由纯JS

处理

假设scores保存JSON数据：

const groups = scores.map(item => item.scores)

const lengths = groups.map(set => set.length)

const max = Math.max(...lengths)

相当优雅（至少在我看来）

旁注：

使用以下方法检索包含结果的“平面”对象：

const flatResults = Array.prototype.concat.apply([],scores.map(item => item.scores)))

Answer 3

您可以将分数map设置为数字数组：data.map(item=>item.scores.map(x=>x.score).map(Number))

然后再次使用reduce映射以获取每个嵌套数组中的最高值：.map(scores=>scores.reduce((result,score)=>Math.max(result,score),0))。每个数据项得分最高。

如果您希望得分最高，可以flat并减少：.flat().reduce((result,score)=>Math.max(result,score),0)

const data = [{"id":5,"project":"name project","scores":[{"id":7,"user_id":30,"implementation_id":5,"score":"12.00","comment":"C'est de la merde, ça vient d’Anthony."},{"id":10,"user_id":31,"implementation_id":5,"score":"15.00","comment":"Super"}]},{"id":6,"project":"name project","scores":[{"id":8,"user_id":30,"implementation_id":6,"score":"20.00","comment":"Super!"},{"id":11,"user_id":31,"implementation_id":6,"score":"12.00","comment":"Super"},{"id":15,"user_id":36,"implementation_id":6,"score":"10.00","comment":"Super"}]}];


console.log(
  'highest per data item:',
  data.map(item=>item.scores.map(x=>x.score).map(Number))
    .map(scores=>scores.reduce((result,score)=>Math.max(result,score),0))
);

console.log(
  'highest over all:',
  data.map(item=>item.scores.map(x=>x.score).map(Number))
    .flat().reduce((result,score)=>Math.max(result,score),0)
);

获取对象的最大值（数字）

3 个答案: