Question

我有疾病和日子的数据。我必须为每种疾病及其感染天数绘制一个地势图。我使用ggplot2进行了尝试。但是，它结合了我不想要的相同疾病的天数。我有兴趣每天绘制每列而不管疾病类型如何。 l使用了以下代码。

original_datafile <-
structure(list(disease = structure(c(1L, 2L, 
3L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 5L, 6L, 6L, 6L), 
.Label = c("AA", "BB", "CC", "DD", "EE", "FF"), 
class = "factor"), days = c(5L, 5L, 9L, 2L, 
3L, 4L, 4L, 5L, 7L, 15L, 3L, 7L, 7L, 15L)), 
class = "data.frame", row.names = c(NA, -14L))  


library(ggplot2)

ggplot(data = original_datafile, aes(x = disease, y = days)) + 
  geom_bar(stat = "identity") + 
  theme(axis.text.x = element_text(angle = 40, hjust = 1))

任何建议将不胜感激。

Answer 1

这是我制定的几个解决方案。不能100％确定这是否是您要追求的目标，但希望这可以使您与您保持联系。为了为每个单独的行创建一个条，而不是将它们组合在一起，我创建了一个名为id的新列，该列仅用作每种疾病的每一行的计数器。然后，我加入了两种可能的ggplot组合，我相信它们会接近您的需求。

original_datafile <-
  structure(list(disease = structure(c(1L, 2L, 
                                       3L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 5L, 6L, 6L, 6L), 
                                     .Label = c("AA", "BB", "CC", "DD", "EE", "FF"), 
                                     class = "factor"), days = c(5L, 5L, 9L, 2L, 
                                                                 3L, 4L, 4L, 5L, 7L, 15L, 3L, 7L, 7L, 15L)), 
            class = "data.frame", row.names = c(NA, -14L))  


library(ggplot2)

# Modified data file adds an 'id' column to split each row individually.

modified_datafile <- original_datafile %>% 
                        group_by(disease) %>% 
                        mutate(id = row_number())

# Facetted ggplot - each disease has its own block

ggplot(data = modified_datafile, aes(x = id, y = days)) + 
  geom_bar(stat = 'identity', position = 'dodge') + 
  theme(axis.text.x = element_text(angle = 40, hjust = 1)) +
  facet_wrap(. ~ disease, nrow = 2) +
  theme(axis.text.x = element_blank()) +
  labs(x = '', y = 'Days')

# Non facetted ggplot - closer to original, but each row has a bar.

ggplot(data = modified_datafile, aes(x = disease, y = days, group = id)) + 
  geom_bar(stat = 'identity', position = position_dodge2(preserve = 'single')) + 
  theme(axis.text.x = element_text(angle = 40, hjust = 1))

使用ggplot的R barplot

1 个答案: