Question

我正在进行Auth0 Lock集成，但出现错误使用未解决的标识符“连接”；您是说“连接”吗？。

.withConnections {_ in
  connections.database(name: "Username-Password-Authentication", requiresUsername: true)
}

我将代码更改为

Connections.database(name: "Username-Password-Authentication", requiresUsername: true)

现在我收到错误消息实例成员'database'不能用于'Connections'类型

当我将代码更改为

Connections().database(name: "Username-Password-Authentication", requiresUsername: true)

遇到错误无法建立“连接”，因为它没有可访问的初始化程序

我将代码更改为

$0.database(name: "Username-Password-Authentication", requiresUsername: true)

获取匿名闭包参数不能在具有显式参数的闭包内使用

https://github.com/auth0/Lock.swift

https://auth0.com/docs/libraries/lock-ios/v2#configuration-options

override func viewDidLoad() {
    super.viewDidLoad()
    // Do any additional setup after loading the view, typically from a nib.

    Lock
        .classic()
        // withConnections, withOptions, withStyle, and so on
        .withOptions {
            $0.oidcConformant = true
            $0.scope = "openid profile"
        }
        .onAuth { credentials in
            // Let's save our credentials.accessToken value
        }
        .withConnections {_ in
            connections.database(name: "Username-Password-Authentication", requiresUsername: true)
        }
        .withStyle {
            $0.title = "Company LLC"
            $0.logo = LazyImage(name: "123.png")
            $0.primaryColor = UIColor(red: 0.6784, green: 0.5412, blue: 0.7333, alpha: 1.0)
        }
        .present(from: self)

Answer 1

似乎Auth0文档在这里是错误的。如果查看Lock.swift source file，则会看到ConnectionBuildable作为参数传递。您需要使用它来建立连接。

尝试一下：

.withConnections { connections in
    connections.database(name: "Username-Password-Authentication", requiresUsername: true)
}

或使用匿名闭包参数的相同操作：

.withConnections {
    $0.database(name: "Username-Password-Authentication", requiresUsername: true)
}

Answer 2

错误位于.withConnections的闭包中您不是通过使用 _

来命名参数的

没有参数

.withConnections { _ in }

带有参数

.withConnections { connections in { connections.database(name: "Username-Password-Authentication", requiresUsername: true) }

Answer 3

您得到使用未解决的标识符“连接”；您是说“连接”吗？，因为connections没有声明为闭包参数。

尝试：

.withConnections { connections in
  connections.database(name: "Username-Password-Authentication", requiresUsername: true)
}

或者如果您想使用匿名参数，请不要声明任何参数：

.withConnections { 
  $0.database(name: "Username-Password-Authentication", requiresUsername: true)
}

使用未解决的标识符“连接”；您是在Auth0中表示“连接”吗？

3 个答案: