Question

我有一个字段，用逗号分隔：

1,2,AA,4,Z
1,ZZ,44,A,1
1,44,33,AA,Z
4,2,Z,A,F
1.2,4,E,1,1
F,1,3.4,3,A

是否可以使用以下规则选择行：数字，数字，字符，任何值？

结果可以是：

1,2,AA,4,Z
4,2,Z,A,F
1.2,4,E,1,1

我正在尝试使用REGEXP_LIKE：

with s as (
select '1,2,AA,4,Z'   val from dual
union all
select '1,ZZ,44,A,1'  val from dual
union all
select '1,44,33,AA,Z' val from dual
union all
select '4,2,Z,A,F'    val from dual
union all
select '1.2,4,E,1,1'  val from dual
union all
select 'F,1,3.4,3,A'  val from dual
)
select val from s where REGEXP_LIKE(val, '(^|,)[[:digit:]](,|$)');

Answer 1

如果您只想返回与模式FQDN:port匹配的行，则此常规表达式应该工作'^([0-9.]*,)([0-9.]*,)([A-Z]+)'

number, number, word, anything

Answer 2

谢谢您的CTE。

这样可以吗？

INTER将每个VAL分成几行
LISTAGG将它们聚合回去，按数字和字符排序

SQL> with s as (
  2  select '1,2,AA,4,Z'   val from dual
  3  union all
  4  select '1,ZZ,44,A,1'  val from dual
  5  union all
  6  select '1,44,33,AA,Z' val from dual
  7  union all
  8  select '4,2,Z,A,F'    val from dual
  9  union all
 10  select '1.2,4,E,1,1'  val from dual
 11  union all
 12  select 'F,1,3.4,3,A'  val from dual
 13  ),
 14  inter as
 15    (select s.val,
 16            regexp_substr(s.val, '[^,]+', 1, t.column_value) c_one
 17     from s, table(cast(multiset(select level from dual
 18                                 connect by level <= regexp_count(s.val, ',') + 1
 19                                ) as sys.odcinumberlist )) t
 20    )
 21  select i.val, listagg(i.c_one, ',') within group
 22                   (order by case when regexp_like(i.c_one, '^\d+|\.|\d+$') then 1
 23                                  when regexp_like(i.c_one, '^[:alpha:]+') then 2
 24                                  else 3
 25                             end) result
 26  from inter i
 27  group by i.val;

VAL          RESULT
------------ --------------------
1,2,AA,4,Z   1,2,4,AA,Z
1,44,33,AA,Z 1,33,44,AA,Z
1,ZZ,44,A,1  1,1,44,A,ZZ
1.2,4,E,1,1  1,1,1.2,4,E
4,2,Z,A,F    2,4,A,F,Z
F,1,3.4,3,A  1,3,3.4,A,F

6 rows selected.

SQL>

按模式返回带有逗号分隔值的行（Oracle SQL）

2 个答案: