Question

我对此并不陌生，如果是重复的问题，我深表歉意。在这一点上，我已经尝试了很多不同的方法，但我不确定这样做的正确方法。

我正在尝试编写一个函数来遍历JSON并获取特定条件（例如：qty != null和sector = 1，position = 1）的模型值。

我还需要计算每个唯一模型的出现次数。任何帮助将不胜感激。

JSON的外观如下。

    [ { "sector": "1", "position": "1", "qty": "1", "model": "SBNHH-1D65C" },
      { "sector": "2", "position": "1", "qty": "1", "model": "" }, 
      { "sector": "3", "position": "1", "qty": "1", "model": "DC6-48-60-18-8F" }, 
      { "sector": "1", "position": "2", "qty": "1", "model": "SBNHH-1D65C" }, 
      { "sector": "2", "position": "2", "qty": "1", "model": "DC6-48-60-18-8F" } ]



public class AntennaItems
{
        public AntennaItems[] root { get; set; }
        public int sector { get; set; }
        public int position { get; set; }
        public string qty { get; set; }
        public string model { get; set; }
}

string requestBodyString = await new StreamReader(req.Body).ReadToEndAsync();

var newJsonString = @"{root:" + requestBodyString + @"}";

List<string> modelList = new List<string>();

var jsonObj = JsonConvert.DeserializeObject<AntennaItems>(newJsonString);

foreach (var elem in jsonObj.root)
{
    modelList.Add(elem.model);
}

return new OkObjectResult($"modelList = {modelList}");

目前，我收到以下答复：

modelList = System.Collections.Generic.List`1[System.String]

Answer 1

我认为您不需要root属性。我对类做了一些修改，并从其中删除了root属性：

ID Mobile      Pref  Email           Pref
1  1234567890   A    test@test.com    A
2  1234567891   A    test@test.com    B

您需要在列表中反序列化它。让我知道是否有帮助。

Answer 2

public class AntennaItems
    {
        public int sector { get; set; }
        public int position { get; set; }
        public string qty { get; set; }
        public string model { get; set; }


        [FunctionName("AntennaSort")]
public static async Task<IActionResult> Run(
            [HttpTrigger(AuthorizationLevel.Function, "get", "post", Route = null)] HttpRequest req,
            ILogger log)
        {
            log.LogInformation("C# HTTP trigger function processed a request.");

            string requestBody = await new StreamReader(req.Body).ReadToEndAsync();

            List<string> modelList = new List<string>();

            var jsonObj = JsonConvert.DeserializeObject<List<AntennaItems>>(requestBody);

            foreach (var elem in jsonObj)
            {
                modelList.Add(elem.model);
            }
            return new OkObjectResult($"modelList = {modelList}");
        }

结果是 modelList = System.Collections.Generic.List`1 [System.String]

Answer 3

您将以字符串名称modelList进行插值，返回modelList，插值将返回modelList的类型，在您的情况下为System.Collections.Generic.List'1[System.String]。

所以这行

return new OkObjectResult($"modelList = {modelList}");

给你

modelList = System.Collections.Generic.List`1[System.String]

因此，与其像上面那样返回，请尝试使用匿名类型返回您的modelList，这样您就可以获取包含modelList的实际数据，例如

return new OkObjectResult(new { modelList = modelList});

或者简单地

return new OkObjectResult(modelList);

C＃有条件地遍历JSON值

3 个答案: