我正在使用PostgreSQL和NodeJS及其“ PG模块”。 CRUD可以工作,但是当我保存或删除某些项目时,有时不会自动更新视图。这是我的代码,我认为错误在这里,但我找不到它,我尝试了所有的方法:'(
错误消息:
const controller = {};
const { Pool } = require('pg');
var connectionString = 'postgres://me:system@localhost/recipebookdb';
const pool = new Pool({
connectionString: connectionString,
})
controller.list = (request, response) => {
pool.query('SELECT * FROM recipes', (err, result) => {
if (err) {
return next(err);
}
return response.render('recipes', { data: result.rows });
});
};
controller.save = (req, res) => {
pool.query('INSERT INTO recipes(name, ingredients, directions) VALUES ($1, $2, $3)',
[req.body.name, req.body.ingredients, req.body.directions]);
return res.redirect('/');
};
controller.delete = (req, res) => {
pool.query('DELETE FROM RECIPES WHERE ID = $1', [req.params.id]);
return res.redirect('/');
}
module.exports = controller;
PD:CRUD有效,但有时会出现该错误。
答案 0 :(得分:3)
当您之前发送响应,然后尝试再次发送响应时,会发生此错误。为此,您必须检查是否有任何一段代码发送了两次响应。有时由于nodejs的异步行为而发生。有时,一个流程将进入事件循环,我们发送响应,完成后,将再次发送响应。因此,您可以使用回调或异步等待来等待执行。
回调
const controller = {};
const { Pool } = require('pg');
var connectionString = 'postgres://me:system@localhost/recipebookdb';
const pool = new Pool({
connectionString: connectionString,
})
controller.list = (request, response) => {
pool.query('SELECT * FROM recipes', (err, result) => {
if (err) {
return next(err);
}
return response.render('recipes', { data: result.rows });
});
};
controller.save = (req, res) => {
pool.query('INSERT INTO recipes(name, ingredients, directions) VALUES ($1, $2,$3)',
[req.body.name, req.body.ingredients, req.body.directions],function(err,resp)
{
if(err){
console.log(err)
}else{
return res.redirect('/');
}
});
};
controller.delete = (req, res) => {
pool.query('DELETE FROM RECIPES WHERE ID = $1', [req.params.id],function(err,resp){
if(err){
console.log(err)
}else{
return res.redirect('/');
}
});
}
module.exports = controller;
或者您也可以使用异步等待来等待执行,然后发送响应。
异步/等待
const controller = {};
const { Pool } = require('pg');
var connectionString = 'postgres://me:system@localhost/recipebookdb';
const pool = new Pool({
connectionString: connectionString,
})
controller.list = async(request, response) => {
try{
const result = await pool.query('SELECT * FROM recipes');
return response.render('recipes', { data: result.rows });
}
catch(err){
return next(err);
}
};
controller.save = async(req, res) => {
try{
await pool.query('INSERT INTO recipes(name, ingredients, directions) VALUES ($1, $2,$3)',[req.body.name, req.body.ingredients, req.body.directions]);
return res.redirect('/');
}
catch(err){
return next(err);
}
};
controller.delete = async(req, res) => {
try{
await pool.query('DELETE FROM RECIPES WHERE ID = $1', [req.params.id]);
return res.redirect('/');
}catch(err){
console.log(err);
}
}
module.exports = controller;
答案 1 :(得分:0)
您需要将响应嵌入到查询的回调中。由于调用是异步的,因此更早发送响应将终止调用堆栈,而无需等待webapi(行为可能会有所不同)。
controller.delete = (req, res) => {
pool.query('DELETE FROM RECIPES WHERE ID = $1', [req.params.id],(err, result)
=> {
// error handling can be done accordingly
return res.redirect('/');
})
}
答案 2 :(得分:0)
检查res.send()
不应调用两次。
在控制器中
const getAll = function(req, res){
res.send(service.getAll(req,res));
}
服务中
const Type = require("../models/type.model.js");
exports.getAll = (req, res) => {
Type.getAll((err, data) => {
res.send(data);
});
};
在 res.send(data); 之上,两次调用会产生问题。更好地使用
const getAll = function(req, res){
service.getAll(req,res);
}