如何将刚刚添加到Firestore数据库中的文档的文档ID添加到所述文档中?
我想这样做,以便当用户检索“乘车”对象并选择预订时,我可以知道他们已经预订了哪个特定的游乐设施。
我面临的问题是,在创建文档ID之前,您无法获得它,因此将其添加到所述文档中的唯一方法是创建文档,读取其ID,然后编辑文档添加ID。大规模地,这将创建所需数量两倍的服务器调用。
是否有标准方法可以做到这一点?还是一个简单的解决方案,可以知道用户预订了哪个“乘车”并在数据库中进行相应的编辑?
struct Ride {
var availableSeats: Int
var carType: String
var dateCreated: Timestamp
var ID: String // How do I implement this?
}
func createRide(ride: Ride, completion: @escaping(_ rideID: String?, _ error: Error?) -> Void) {
// Firebase setup
settings.areTimestampsInSnapshotsEnabled = true
db.settings = settings
// Add a new document with a generated ID
var ref: DocumentReference? = nil
ref = db.collection("rides").addDocument(data: [
"availableSeats": ride.availableSeats,
"carType": ride.carType,
"dateCreated": ride.dateCreated,
"ID": ride.ID,
]) { err in
if let err = err {
print("Error adding ride: \(err)")
completion(nil, err)
} else {
print("Ride added with ID: \(ref!.documentID)")
completion(ref?.documentID, nil)
// I'd currently have to use this `ref?.documentID` and edit this document immediately after creating. 2 calls to the database.
}
}
}
答案 0 :(得分:2)
尽管有一个很好的答案,但FireStore具有您所需的内置功能,并且不需要两次调用数据库。实际上,它不需要任何对数据库的调用。
这是一个例子
let testRef = self.db.collection("test_node")
let someData = [
"child_key": "child_value"
]
let aDoc = testRef.document() //this creates a document with a documentID
print(aDoc.documentID) //prints the documentID, no database interaction
//you could add the documentID to an object etc at this point
aDoc.setData(someData) //stores the data at that documentID
有关更多信息,请参见文档Add a Document。
在某些情况下,使用 自动生成的ID,然后在以后使用参考。对于此用例, 您可以调用doc():
您可能要考虑略有不同的方法。您也可以在写入后在闭包中获取文档ID。因此,让我们给您一个酷骑(课程)
class RideClass {
var availableSeats: Int
var carType: String
var dateCreated: String
var ID: String
init(seats: Int, car: String, createdDate: String) {
self.availableSeats = seats
self.carType = car
self.dateCreated = createdDate
self.ID = ""
}
func getRideDict() -> [String: Any] {
let dict:[String: Any] = [
"availableSeats": self.availableSeats,
"carType": self.carType,
"dateCreated": self.dateCreated
]
return dict
}
}
然后是一些代码来创建游乐设施,将其写出并利用其自动创建的documentID
var aRide = RideClass(seats: 3, car: "Lincoln", createdDate: "20190122")
var ref: DocumentReference? = nil
ref = db.collection("rides").addDocument(data: aRide.getRideDict() ) { err in
if let err = err {
print("Error adding document: \(err)")
} else {
aRide.ID = ref!.documentID
print(aRide.ID) //now you can work with the ride and know it's ID
}
}
答案 1 :(得分:1)
我相信,如果您使用UUID
框架提供的Swift内置ID生成器,称为Foundation
,这将使您可以做自己想做的事情。请参阅以下代码,了解我的建议更改。同样通过这种方式,当您首次初始化“ Ride”结构时,可以生成其ID变量,而不是在函数内部进行操作。这是我在整个应用程序中生成唯一ID的方式,并且效果很好!希望这会有所帮助!
struct Ride {
var availableSeats: Int
var carType: String
var dateCreated: Timestamp
var ID: String
}
func createRide(ride: Ride, completion: @escaping(_ rideID: String, _ error: Error?) -> Void) {
// Firebase setup
settings.areTimestampsInSnapshotsEnabled = true
db.settings = settings
// Add a new document with a generated ID
var ref: DocumentReference? = nil
let newDocumentID = UUID().uuidString
ref = db.collection("rides").document(newDocumentID).setData([
"availableSeats": ride.availableSeats,
"carType": ride.carType,
"dateCreated": ride.dateCreated,
"ID": newDocumentID,
], merge: true) { err in
if let err = err {
print("Error adding ride: \(err)")
completion(nil, err)
} else {
print("Ride added with ID: \(newDocumentID)")
completion(newDocumentID, nil)
}
}
}
答案 2 :(得分:1)
这是我的解决方案,就像一个魅力
let opportunityCollection = db.collection("opportunities")
let opportunityDocument = opportunityCollection.document()
let id = opportunityDocument.documentID
let data: [String: Any] = ["id": id,
"name": "Kelvin"]
opportunityDocument.setData(data) { (error) in
if let error = error {
completion(.failure(error))
} else {
completion(.success(()))
}
}