Question

Php简单代码可“保护”内容。

<?php if(isset($_POST['submit'])) { ?>

// protected content \\

<?php } else { ?>

<form action="" method="post">
<button type="submit" name="submit">click to view protected content</button>
</form>

<?php } ?>

现在，当我点击“提交”按钮时，我尝试添加验证码... 但是当我解析验证码时，不要重定向隐藏内容

<script src="https://www.google.com/recaptcha/api.js" async defer></script>
<form action="" method="post">
<button class="g-recaptcha" data-sitekey="6LdVvYQUAAAAAIVD_yRB8nBeajeEChQjXhhSldHj" type="submit" name="submit">view protected content</button>
</form>

Answer 1

我认为您忘了在JS下面添加

<script>
function onSubmit(token) {
    document.getElementById("your-form").submit();
}
</script>

请记住将表格更改为

<form action="" method="post" id="your-form">
    <button class="g-recaptcha" data-sitekey="6LdVvYQUAAAAAIVD_yRB8nBeajeEChQjXhhSldHj" name="submit" data-callback="onSubmit">view protected content</button>
</form>

表单提交与验证码冲突

1 个答案: