Question

我需要使mousePressed（）函数在其长度（r1和r2 = 200）的范围内移动整个摆。第32-44行需要根据mousePressed函数进行更改

我有一个单独的摆锤的代码，该摆锤使用PGraphics并具有我想要的功能。它使用摆的长度作为球末端的最大位移。我需要将其转换为一个双摆，该双摆占两个长度而不是一个长度。运行该程序一段时间后，将跟踪的线绑定到一个圆中，半径为r变量（400）的总和。

void drag() {
// If we are draging the ball, we calculate the angle between the 
// pendulum origin and mouse position
// we assign that angle to the pendulum
if (dragging) {
  PVector diff = PVector.sub(origin, new PVector(mouseX, mouseY));      // Difference between 2 points
  angle = atan2(-1*diff.y, diff.x) - radians(90);                      // Angle relative to vertical axis
}

} }

float r1 = 200;
float r2 = 200;
float m1 = 40;
float m2 = 40;
float a1 = PI/2;
float a2 = PI/2;
float a1_v = 0;
float a2_v = 0;
float g = 1;

float px2 = -1;
float py2 = -1;
float cx, cy;

PGraphics canvas;

void setup() {
  size(1024, 768);
  cx = width/2;
  cy = 200;
  canvas = createGraphics(width, height);
  canvas.beginDraw();
  canvas.background(255);
  canvas.endDraw();
}

void draw() {
  background(255);
  imageMode(CORNER);
  image(canvas, 0, 0, width, height);

  float num1 = -g * (2 * m1 + m2) * sin(a1);
  float num2 = -m2 * g * sin(a1-2*a2);
  float num3 = -2*sin(a1-a2)*m2;
  float num4 = a2_v*a2_v*r2+a1_v*a1_v*r1*cos(a1-a2);
  float den = r1 * (2*m1+m2-m2*cos(2*a1-2*a2));
  float a1_a = (num1 + num2 + num3*num4) / den;

  num1 = 2 * sin(a1-a2);
  num2 = (a1_v*a1_v*r1*(m1+m2));
  num3 = g * (m1 + m2) * cos(a1);
  num4 = a2_v*a2_v*r2*m2*cos(a1-a2);
  den = r2 * (2*m1+m2-m2*cos(2*a1-2*a2));
  float a2_a = (num1*(num2+num3+num4)) / den;

  translate(cx, cy);
  stroke(0);
  strokeWeight(2);

  float x1 = r1 * sin(a1);
  float y1 = r1 * cos(a1);

  float x2 = 0;
  float y2 = 0;

  if(mousePressed){
    x2 = mouseX - cx;
    y2 = mouseY - cy;
  }else{
    x2 = x1 + r2 * sin(a2);
    y2 = y1 + r2 * cos(a2);  
  }

  line(0, 0, x1, y1);
  fill(0);
  ellipse(x1, y1, m1, m1);

  line(x1, y1, x2, y2);
  fill(0);
  ellipse(x2, y2, m2, m2);

  a1_v += a1_a;
  a2_v += a2_a;
  a1 += a1_v;
  a2 += a2_v;

  // a1_v *= 0.99;
  // a2_v *= 0.99;

  canvas.beginDraw();
  //canvas.background(0, 1);
  canvas.translate(cx, cy);
  canvas.stroke(0);
  if (frameCount > 1) {
    canvas.line(px2, py2, x2, y2);
   }
  canvas.endDraw();


  px2 = x2;
  py2 = y2;
}

如何通过鼠标交互重做双摆加速公式

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