Question

我有一个3 SQL表，其中包含树节点和树叶以及节点描述我想以以下格式打印数据

Parent6 Parent5 Parent4 Parent3 Parent1 Child Description
                 A1
                         B1
                                 C1    
                                          D1A  - Child 1
                                          D1B  - Child 2
                                 C2
                                          D2A - Child 3
                                          D2B - Child 4
                         B2

我在节点表中有TreeNodeNuM，TreeName，级别

Answer 1

我为类似的事情编写了这段代码，通常我只使用LongID和LongDescription列满足我的需要，我添加了一些案例以使输出类似于您的示例，请注意，对于我的层次结构，该级别从0开始

WITH cte AS
  (
    SELECT     CAST(RIGHT('000' + CAST(HierarchyID AS VARCHAR),3) AS VARCHAR(100)) as M,
               CAST(Description AS VARCHAR(MAX)) AS LongID, *
    FROM       HIERARCHY
    WHERE Level = 0
    UNION ALL
    SELECT     CAST(cte.M + '_' + RIGHT('000' + CAST(si.HierarchyID AS varchar), 3) AS VARCHAR(100)),
               CAST(cte.LongID + '->' + si.Description AS VARCHAR(MAX)),
               si.*
    FROM       HIERARCHY si
    INNER JOIN cte
    ON si.ParentHierarchyID = cte.HierarchyID
  )
  SELECT 
  CASE WHEN Level = 0 THEN Description ELSE '' END AS Parent6,
  CASE WHEN Level = 1 THEN Description ELSE '' END AS Parent5,
  CASE WHEN Level = 2 THEN Description ELSE '' END AS Parent4,
  CASE WHEN Level = 3 THEN Description ELSE '' END AS Parent3,
  CASE WHEN Level = 4 THEN Description ELSE '' END AS Parent1,
  CASE WHEN Level = 5 THEN Description ELSE '' END AS Child, 
  FROM cte
  ORDER BY LongID

在层次结构中以空白和空白打印树数据

1 个答案: