Question

你好，我有以下问题。我正在尝试模拟注入执行程序的调用立即执行给定的Callable。稍后在测试中，将调用Callable内部调用的方法的参数，并声明参数。模拟示例，请参见下面。

Maven 3，jdk 10-slim，mockk 1.9

    //this task should be executed by executor
    private val taskCaptor = slot<Callable<Boolean>>()
    private val asyncTaskExecutor: LazyTraceThreadPoolTaskExecutor = mockk<LazyTraceThreadPoolTaskExecutor>().apply {
        //this was my 1st try, but resutt was java.lang.InstantiationError: java.util.concurrent.Callable
        //every { submit(capture(taskCaptor)) } returns CompletableFuture.completedFuture(taskCaptor.captured.call())
        //every { submit(any()) } returns CompletableFuture.completedFuture(true)
        every { submit(ofType(Callable::class)) } returns FutureTask<Boolean>(Callable { true })
    }

后来，我将Callable接口更改为实现，该接口是在经过测试的类中创建的，并且遇到了另一个异常。与上述代码相同的是

java.lang.InstantiationError: java.util.concurrent.Future

这是submit方法的返回类型。

我嘲笑的方法是错误的吗？

Answer 1

不确定这是否是最好的实现方式，但对我来说，它是这样工作的：

    private val taskCaptor = slot<Callable<Boolean>>()
    private val asyncTaskExecutor: LazyTraceThreadPoolTaskExecutor = mockk<LazyTraceThreadPoolTaskExecutor>().apply {
        every { submit(ofType(Callable::class)) } returns mockFuture
        every { mockFuture.get() } returns true

    }

MockK模拟方法返回Interface Future

1 个答案: