我需要从文本文件中提取字符,并将它们的行专业顺序存储在2字符数组中,即20 x45。然后,我需要打印出存储的字符专业行。这需要使用任何大小的文本文件。据我所知,这段代码我还无法将其打印在专业栏上。
package myfirstjavaproject;
import java.io.*;
import java.util.Scanner;
public class temp {
public static void main(String[] args)throws Exception{
File file = new File ("test.txt");
BufferedReader br = new BufferedReader(new FileReader(file));
String st = br.readLine();
int row = 20, column = 45;
int offset = 0;
char[][] array = new char [row][column];
for (int i = 0; i < row; i++) {
for(int j = 0; j < column; j++) {
array[i][j] = st.charAt(offset++);
System.out.print(array[i][j]);
}
System.out.println();
}
}
}
此代码将其打印出来,然后出现错误消息。
Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 55
at java.lang.String.charAt(Unknown Source)
at myfirstjavaproject.temp.main(temp.java:18)
答案 0 :(得分:0)
/ *我想您正在尝试以下操作:您可能想使用stringbuilder或stringbuffer代替String * /
public static void main(String[] args)throws Exception{
File file = new File ("test.txt");
BufferedReader br = new BufferedReader(new FileReader(file));
String st = br.readLine();
String s = null;
while(br.read()!=-1)
{
s=s+br.readLine();
}
int row = 20, column = 45;
int offset = 0;
char[][] array = new char [row][column];
for (int i = 0; i < row; i++) {
for(int j = 0; j < column; j++) {
array[i][j] = s.charAt(offset++);
System.out.print(array[i][j]);
}
System.out.println();
}
}
答案 1 :(得分:0)
st.length
可能不够长。
if (st != null && st.length() < offset) {
st = br.readLine();
}