setInterval有效,但延迟了一个周期

时间:2019-01-21 01:09:00

标签: javascript setinterval

我的目标是每四秒钟显示一次数组中的单词,除非用户在不到四秒钟的时间内正确输入单词,在这种情况下,间隔会被清除并重新启动。当我单击“开始”时,会在单词显示前四秒钟过去。我希望它立即显示,此后每隔四秒显示一次,除非用户在四秒之前键入正确的单词,在这种情况下,清除间隔并重新启动间隔,在这种情况下,在显示下一个单词之前会有四秒钟的延迟。为什么间隔在执行操作之前要经过一次计数。我怎样才能解决这个问题?我对jquery不熟悉,因此请在js`中提供一些建议

startBtn.addEventListener('click', startGame);
answerBox.addEventListener('keyup', checkWord);


function startGame() {
    //showWord();
    gameTimer = setInterval(gameTime, 1000);
    timedWordDisplay = setInterval(showWord, 4000);
    }



function checkWord() {
    let currentWordLen = answerBox.value.length;
    if (wordDisplayBox.innerHTML === answerBox.value) {
        clearInterval(timedWordDisplay);
        numWordsRight++;
        numGoodWordsField.innerHTML = numWordsRight;
        answerBox.value = '';
        answerBox.focus();
        wordDisplayBox.innerHTML = '';
        timedWordDisplay = setInterval(showWord, 4000);
    } else if (answerBox.value === currentWord.substring(0, currentWordLen)) {
             answerBox.style.borderColor = 'green';
    } else {
      answerBox.style.borderColor = 'red';
    }
    
        
    
}

/* function checkWord() {
    let currentWordLen = answerBox.value.length;
    if (wordDisplayBox.innerHTML === answerBox.value) {
        clearInterval(showWord);
        goodScore++;
        numGoodWordsField.innerHTML = goodScore;
        answerBox.value = '';
        answerBox.focus();
        setInterval(showWord,4000);
    } else if (answerBox.value === currentWord.substring(0,currentWordLen)) {
      answerBox.style.backgroundColor = 'green';
    } else {
      answerBox.style.backgroundColor = 'red';
    }
    
}
*/

function showWord() {
    answerBox.focus();
    console.log('show word func start');
    console.log('seconds between ' + time);
    let randomNum = Math.floor(Math.random()*wordsLevelOne.length);
        console.log('random number is:' + randomNum);
    currentWord = wordsLevelOne[randomNum];
    console.log('curentWord is ' + currentWord);
    wordDisplayBox.innerHTML = currentWord;
    //setInterval(wordTime, 1000);
    //showWord();
}

1 个答案:

答案 0 :(得分:-1)

您可以使用 setTimeout clearTimeout 重置

var tmr;
function startTimer() {
    tmr = setTimeout(showWord, 4000);
}

function stopTimer() {
    if(tmr) {
        clearTimeout(tmr);
    }
}