如何为所有模态制作一个脚本?

时间:2019-01-20 20:40:32

标签: javascript html5 css3 bootstrap-4 bootstrap-modal

在同一页面上,我大约有十二个图像,单击每个图像可以打开模态。我为每个模态制作了一个脚本,如何为所有模态制作一个脚本?

<!-- 1 Modal-->
<div class="gallery_product col-lg-3 col-md-3 col-sm-3 col-xs-3 filter mercoledì ombra">
<img onclick="myLele(this)" src="https://www.festadellamusicact.it/wp-content/uploads/leletronika.jpg" id="myImg" class="img-responsive"></div>
<div id="lele" class="modal">
<div class="modal-content" id="img11">
<span onclick="undici.style.display = 'none'" class="close">&times;</span>
<img src="https://www.festadellamusicact.it/wp-content/uploads/33407528_10216104175664929_3838668853781463040_n.jpg" class="img-responsive img-modale"></div>
</div> 
<!-- 2 Modal-->
<div class="gallery_product col-lg-3 col-md-3 col-sm-3 col-xs-3 filter mercoledì ombra">
<img onclick="myJessy(this)" src="https://www.festadellamusicact.it/wp-content/uploads/jessy.jpg" id="myImg" class="img-responsive"></div>
<div id="jessy" class="modal">
<div class="modal-content" id="img10">
<span onclick="dieci.style.display = 'none'" class="close">&times;</span>
<img src="https://www.festadellamusicact.it/wp-content/uploads/29543_497687346938913_28179288_n.jpg" class="img-responsive img-modale">
<script>
   var undici = document.getElementById('lele');
   var lele = document.getElementById("img11");

function myLele(el) {
        var ImgSrc = el.src;
        undici.style.display = "block";
        lele.src = ImgSrc;
    }
    window.onclick = function (event) {
        if (event.target == undici) {
            undici.style.display = "none";
        }
    }
</script>
<script>
    var dieci = document.getElementById('jessy');
    var jessy = document.getElementById("img10");

function myJessy(el) {
        var ImgSrc = el.src;
        dieci.style.display = "block";
        jessy.src = ImgSrc;
    }
    window.onclick = function (event) {
        if (event.target == dieci) {
            dieci.style.display = "none";
        }
    }
</script>

我尝试了不同的方法,但是在同一页面上的多个模式上却不起作用。 我可以做一个foreach()循环吗?

1 个答案:

答案 0 :(得分:1)

每个元素的

ID应该唯一。将两个图像的ID分别从myImg更改为myImg1myImg2之类的唯一名称。

此外,您无需编写自定义函数即可切换模态。只需在Bootstrap中使用内置模式,只需将data-toggle="modal" data-target="#lele"添加到模式1图像并将data-toggle="modal" data-target="#jessy"添加到模式2图像即可,如下所示:

<img src="/leletronika.jpg" id="myImg1" class="img-responsive" data-toggle="modal" data-target="#lele">
<img src="/jessy.jpg" id="myImg2" class="img-responsive" data-toggle="modal" data-target="#jessy">

您还需要像这样将data-dismiss属性添加到关闭按钮:

<span class="close" data-dismiss="modal">&times;</span>

检查并运行以下代码段,以获得上述内容的实际示例:

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script><script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.0/umd/popper.min.js"></script><script src="https://stackpath.bootstrapcdn.com/bootstrap/4.1.0/js/bootstrap.min.js"></script>
<link href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.0/css/bootstrap.min.css" rel="stylesheet"/>

<!-- 1 Modal-->
<div class="gallery_product col-lg-3 col-md-3 col-sm-3 col-xs-3 filter mercoledì ombra">
  <img src="https://www.festadellamusicact.it/wp-content/uploads/leletronika.jpg" id="myImg1" class="img-responsive" data-toggle="modal" data-target="#lele">
</div>
<div id="lele" class="modal">
  <div class="modal-content" id="img11">
    <span class="close" data-dismiss="modal">&times;</span>
    <img src="https://www.festadellamusicact.it/wp-content/uploads/33407528_10216104175664929_3838668853781463040_n.jpg" class="img-responsive img-modale">
  </div>
</div> 
<!-- 2 Modal-->
<div class="gallery_product col-lg-3 col-md-3 col-sm-3 col-xs-3 filter mercoledì ombra">
  <img src="https://www.festadellamusicact.it/wp-content/uploads/jessy.jpg" id="myImg2" class="img-responsive" data-toggle="modal" data-target="#jessy">
</div>
<div id="jessy" class="modal">
  <div class="modal-content" id="img10">
    <span class="close" data-dismiss="modal">&times;</span>
    <img src="https://www.festadellamusicact.it/wp-content/uploads/29543_497687346938913_28179288_n.jpg" class="img-responsive img-modale">
  </div>