Question

如何使此旧版本的php在php7中工作？我有一个mysql数据库，用于发布我在Construct 2中创建的游戏中的高分。但是现在它已停止工作，因为我的主机已更新为php7（此刻我可以在php 7.1-7.3之间进行选择）

我已经尝试了很长时间，在网络上搜索，以使其再次运行，但仍无法解决它。

我有2个php文件：getscores.php和savescores.php

当我尝试在网络浏览器（Chrome）中查看getscores.php时，出现错误：致命错误：未捕获错误：调用未定义函数mysql_query（） ...这是指第18行。

对不起，但是我几乎不了解php和mysql数据库

如果有任何可以帮助的人，在此先非常感谢您。 :) ///灵魂机器！

getscores.php

<?php
header('Access-Control-Allow-Origin: *');

$host="localhost"; // Host name 
$username="username"; // Mysql username 
$password="password"; // Mysql password 
$db_name="database"; // Database name 
$tbl_name="scores"; // Table name

// Connect to server and select database.
$link = mysqli_connect("$host", "$username", "$password", "$db_name");

// Retrieve data from database
$sql="SELECT * FROM scores ORDER BY score DESC LIMIT 10";   // The 'LIMIT                 10' part will only read 10 scores. Feel free to change this value
$result=mysql_query($sql);

// Start looping rows in mysql database.
while($rows=mysqli_fetch_array($result)){
echo $rows['name'] . "|" . $rows['score'] . "|";

// close while loop 
}

// close MySQL connection 
mysql_close();
?>

savescores.php

<?php

$db = "database";//Your database name
$dbu = "username";//Your database username
$dbp = "password";//Your database users' password
$host = "localhost";//MySQL server - usually localhost

$dblink = mysqli_connect($host,$dbu,$dbp,$db);

if(isset($_GET['name']) && isset($_GET['score'])){

 //Lightly sanitize the GET's to prevent SQL injections and possible XSS     attacks
 $name = strip_tags(mysql_real_escape_string($_GET['name']));
 $score = strip_tags(mysql_real_escape_string($_GET['score']));

 $sql = mysqli_query($dblink, "INSERT INTO `$db`.`scores` (`id`,`name`,`score`) VALUES ('','$name','$score');");
 if($sql){

      //The query returned true - now do whatever you like here.
      echo 'Your score was saved. Congrats!';

 }else{

      //The query returned false - you might want to put some sort of error reporting here. Even logging the error to a text file is fine.
      echo 'There was a problem saving your score. Please try again later.';

 }

}else{
 echo 'Your name or score wasnt passed in the request. Make sure you add ?    name=NAME_HERE&score=1337 to the tags.';
}

mysqli_close($dblink);//Close off the MySQL connection to save resources.
?>

Answer 1

分别用mysql_query和mysql_close替换mysqli_query和mysqli_close。

<?php
header('Access-Control-Allow-Origin: *');

$host="localhost"; // Host name 
$username="username"; // Mysql username 
$password="password"; // Mysql password 
$db_name="database"; // Database name 
$tbl_name="scores"; // Table name

// Connect to server and select database.
$link = mysqli_connect("$host", "$username", "$password", "$db_name");

// Retrieve data from database
$sql="SELECT * FROM scores ORDER BY score DESC LIMIT 10";   // The 'LIMIT                 10' part will only read 10 scores. Feel free to change this value
$result=mysqli_query($link, $sql);

// Start looping rows in mysql database.
while($rows=mysqli_fetch_array($result)){
echo $rows['name'] . "|" . $rows['score'] . "|";

// close while loop 
}

// close MySQL connection 
mysqli_close($link);
?>

这应该有效。

如何在php7中更改旧版本的php工作

1 个答案: