Question

如果答案有误，如何使函数重复，所以程序将选择一个新的数字。

进行while循环

import random, sys

def randomNumber(diceRoll):

    while True:
        print('Pick a number 1 to 6')
        userEntry = int(input())

        if diceRoll == userEntry:
            print('Correct')
            sys.exit()

        if diceRoll != userEntry:
            print('Wrong, try again')
            print('The number generated was ' + str(diceRoll))
            continue

r = random.randint(1, 6)
outcome = randomNumber(r)

如果用户猜错了，我希望程序再次询问用户随机数，但是使用新的数字。

Answer 1

如果猜错了，只需重置diceRoll。

import random, sys

def randomNumber(diceRoll):

    while True:
        print('Pick a number 1 to 6')
        userEntry = int(input())

        if diceRoll == userEntry:
            print('Correct')
            sys.exit()

        if diceRoll != userEntry:
            print('Wrong, try again')
            print('The number generated was ' + str(diceRoll))
            diceRoll = random.randint(1, 6)
            continue

r = random.randint(1, 6)
outcome = randomNumber(r)

如何使功能重复？

1 个答案: