参数未加在一起

Question

//已解决

我正在尝试将参数加在一起，然后将其除以2，以便将结果传递给sqrt方法。经过一番排解，我发现它只是返回函数的最后一个参数。

typeOf返回参数是数字，所以我不确定发生了什么。

function areaTriangle(a,b,c) {
    let area, perimeter; 

    perimeter = (a + b + c)/2;
    //heron's formula
    area = Math.sqrt(perimeter * ((perimeter - a)  * (perimeter - b) * (perimeter = c)));

    return area;
}

//areaTriangle(3,3,9) perimeter returns 9(arg of c). Should be 7.5.

Answer 1

更改

area = Math.sqrt(perimeter * ((perimeter - a) * (perimeter - b) * (perimeter = c)));

到

area = Math.sqrt(perimeter * ((perimeter - a) * (perimeter - b) * (perimeter - c)));