我正在尝试遍历作为响应收到的嵌套JSON。
这是响应:
{
"nextPageToken": "CAUQAA",
"items": [
{
"contentDetails": {
"videoPublishedAt": "2009-09-23T11:07:45.000Z",
"videoId": "1zagQpB_c0M"
},
"kind": "youtube#playlistItem",
"etag": "\"XpPGQXPnxQJhLgs6enD_n8JR4Qk\/NW6JAIYqE0f-uUkRnhYDTMiJ1nw\"",
"id": "UEwwUDR2SVRPd1k0VGFyNXhxeUhCbllPd0Z4TDRpc1d0VS41NkI0NEY2RDEwNTU3Q0M2"
},
{
"contentDetails": {
"videoPublishedAt": "2007-11-26T01:23:19.000Z",
"videoId": "GoCOg8ZzUfg"
},
"kind": "youtube#playlistItem",
"etag": "\"XpPGQXPnxQJhLgs6enD_n8JR4Qk\/ogX8pxR3cwm0xA6DQhc7j_tuuHw\"",
"id": "UEwwUDR2SVRPd1k0VGFyNXhxeUhCbllPd0Z4TDRpc1d0VS4yODlGNEE0NkRGMEEzMEQy"
},
{
"contentDetails": {
"videoPublishedAt": "2008-07-08T17:39:12.000Z",
"videoId": "6Y-DjurrO08"
},
"kind": "youtube#playlistItem",
"etag": "\"XpPGQXPnxQJhLgs6enD_n8JR4Qk\/NNzmeRr-3TfKHRfxmkOArbnNSII\"",
"id": "UEwwUDR2SVRPd1k0VGFyNXhxeUhCbllPd0Z4TDRpc1d0VS45ODRDNTg0QjA4NkFBNkQy"
},
{
"contentDetails": {
"videoPublishedAt": "2009-07-05T13:31:44.000Z",
"videoId": "_EQYndFqMS0"
},
"kind": "youtube#playlistItem",
"etag": "\"XpPGQXPnxQJhLgs6enD_n8JR4Qk\/90b0La1GsJV5pfaAYn0Kd7OJpWA\"",
"id": "UEwwUDR2SVRPd1k0VGFyNXhxeUhCbllPd0Z4TDRpc1d0VS4xM0YyM0RDNDE4REQ1NDA0"
}
],
"kind": "youtube#playlistItemListResponse",
"etag": "\"XpPGQXPnxQJhLgs6enD_n8JR4Qk\/TwSA9klp7PJcoEjYfML5mdmYI-0\"",
"pageInfo": {
"resultsPerPage": 5,
"totalResults": 55
}
}
我尝试(并成功)访问了我的词典的外部层次。另外,我可以对需要的内容进行硬编码,见下文。
对需要的数据进行硬编码访问
print data['items'][0]['contentDetails']['videoId']:
这就是我试图遍历响应的方式:
for i in data['items'][0]['contentDetails']['videoId']:
print i
上面的for循环将循环我'videoID'具有的字符数。
如何使用for循环访问每个“ videoID” json元素?
答案 0 :(得分:1)
您需要遍历项目:
for item in data['items']:
print item['contentDetails']['videoId']
答案 1 :(得分:0)
我是afk,所以我不能给你代码,但您可能想看看json包,它简化了数据结构的处理。至少在我看来尤其如此... Sorrz评分过低,无法添加答案而不是答案