Question

假设我有一个如下表：

employee | period  | commission
A        | 1Y      | 100
A        | 2Y      | 150
B        | 1Y      | 80
C        | 1Y      | 200
C        | 2Y      | 270
C        | 6M      | 80

此数据显示员工根据时间段赚取的佣金。现在，我需要在node.js代码中以以下格式获取数据

[
  {
    "employee": "A",
    "commission": [
      {
        "period": "1Y",
        "commission": 100
      },
      {
        "period": "2Y",
        "commission": 150
      }
    ]
  },
  {
    "employee": "B",
    "commission": [
      {
        "period": "1Y",
        "commission": 80
      }
    ]
  },
  {
    "employee": "C",
    "commission": [
      {
        "period": "6M",
        "commission": 80
      },
      {
        "period": "1Y",
        "commission": 200
      },
      {
        "period": "2Y",
        "commission": 270
      }
    ]
  }
]

我写了以下查询

select 
  employee, 
  json_agg (json_build_object('period', period, 'commission', commission)) as commission 
from 
  table_name 
  group by employee

此查询给了我想要的结果，但现在我也想根据特定时期内获得的佣金对员工进行排序例如根据期间='1Y'赚取的佣金对员工进行排序。我无法通过此查询找到解决方案。请为此类问题提供其他好的解决方案

Answer 1

在查询中提取一年的佣金，并在包装查询中使用该佣金对结果进行排序：

select employee, commission
from (
    select 
        employee, 
        json_agg (json_build_object('period', period, 'commission', commission)) as commission,
        max(case period when '1Y' then commission end) as one_year_commission
    from table_name 
    group by employee
    ) s
order by one_year_commission

Answer 2

我将其表示为：

select employee, 
       json_agg(json_build_object('period', period, 'commission', commission)) as commission 
from table_name 
group by employee
order by sum(commission) filter (where period = '1Y');

不需要子查询。

如何根据以下条件对查询结果进行排序？

2 个答案: