与this question相关,但正在扩展 - 我如何在表单集中使用此技术?
我想在表单中使用当前登录的用户,但我在formset中使用该表单。单个表单的引用解决方案是将request.user传递给init中的表单和进程。如何为formset中的每个表单添加kwargs?
我的代码示例:
在forms.py
中class NewStudentForm (forms.Form):
username = forms.RegexField(label=_("Username"), max_length=30, regex=r'^\w+$',
help_text = _("Required. 30 characters or fewer. Alphanumeric characters only (letters, digits and underscores)."),
error_message = _("This value must contain only letters, numbers and underscores."))
first_name = forms.CharField(label=_('first name'), max_length=30 )
last_name = forms.CharField(label=_('last name'), max_length=30, )
email = forms.EmailField(label=_('e-mail address') )
password = forms.CharField(label=_('password'), max_length=64, )
class Meta:
model = User
fields = ("username","first_name", "last_name", "email", "password")
def __init__(self, *args, **kwargs):
self._user = kwargs.pop('user')
super(NewStudentForm, self).__init__(*args, **kwargs)
def save(self, commit=True):
user = super(NewStudentForm, self).save(commit=False)
user.set_password(self.cleaned_data["password"])
if commit:
user.save()
profile = Profile.objects.create_profile(user)
profile.activiation_key = profile.ACTIVATED_KEY
profile.authorized = True
profile.save()
user.is_active=True
user.save()
student = models.Student()
student.user = user
student.teacher = self._user
student.plaintext_pwd = self.cleaned_data["password"]
student.save()
return UserWarning
然后在views.py
中@login_required
def new_student(request):
from django.forms.formsets import formset_factory
try:
if request.method == 'GET':
newStudentFormset = formset_factory(forms.NewStudentForm, extra=2)
formset = newStudentFormset()
return shortcuts.render_to_response('NewStudent.html', { 'newStudentFormSet':formset, 'active_username': request.user.username })
elif request.method == 'POST':
if LOGIN_FORM_KEY in request.POST:
return _handle_login(request)
data = request.POST.copy()
newStudentFormset = formset_factory(forms.NewStudentForm)
formset = newStudentFormset(data) ### Pass current user to formset? ###
if formset.is_valid():
formset.save()
request.user.message_set.create(message="Save successful.")
return shortcuts.redirect(student)
else:
return shortcuts.render_to_response('NewStudent.html', { 'newStudentFormSet':formset, 'active_username': request.user.username, 'error_message':formset.errors})
return http.HttpResponseNotAllowed(['GET', 'POST'])
except models.Student.DoesNotExist:
return http.HttpResponseNotFound('<h1>Requested Student not found</h1>')
答案 0 :(得分:19)
通过添加扩展BaseFormSet
的类,您可以添加自定义代码以将参数传递给表单。
forms.py
中的:
class NewStudentFormSet(BaseFormSet):
def __init__(self, *args, **kwargs):
self.user = kwargs.pop('user', None)
super(NewStudentFormSet, self).__init__(*args, **kwargs)
def _construct_forms(self):
self.forms = []
for i in xrange(self.total_form_count()):
self.forms.append(self._construct_form(i, user=self.user))
然后在views.py
:
# ...
data = request.POST.copy()
newStudentFormset = formset_factory(forms.NewStudentForm, formset=forms.NewStudentFormSet)
formset = newStudentFormset(data, user=request.user)
# ...
感谢Ashok Raavi。
答案 1 :(得分:6)
我宁愿直接在视图中迭代表单:
for form in formset.forms:
form.user = request.user
formset.save()
答案 2 :(得分:4)
基于保罗检查答案(对我的案例不起作用)。
我喜欢不编写自定义BaseFormSet继承类的想法。
if formset.is_valid():
new_instances = formset.save(commit=False)
for new_instance in new_instances:
new_instance.user = request.user
new_instance.save()
答案 3 :(得分:2)
我尝试了自相似的解决方案,但BaseFormSet
在我的Django 1.6中没有用。
我按照以下步骤操作:https://code.djangoproject.com/ticket/17478,对我有用的方法是:
class NewStudentFormSet(BaseFormSet):
def __init__(self, *args, **kwargs):
self.user = kwargs.pop('user',None)
super(NewStudentFormSet, self).__init__(*args, **kwargs)
for form in self.forms:
form.empty_permitted = False
def _construct_forms(self):
if hasattr(self,"_forms"):
return self._forms
self._forms = []
for i in xrange(self.total_form_count()):
self._forms.append(self._construct_form(i, user=self.user))
return self._forms
forms = property(_construct_forms)
答案 4 :(得分:0)
以下是关于将表单参数传递给表单集的类似问题:
Django Passing Custom Form Parameters to Formset
就个人而言,我喜欢关于在函数中动态构建表单类的第二个答案,因为它实现起来非常快且易于理解。