How to rotate matplotlib fill-style-markers?

Question

In black are matplotlib markers that are able to rotate . In blue/orange are fill-style-markers, and I have not managed to rotate them in the same way.

Here is the code that has generated the graphics. In this version t is not used.

import matplotlib as mpl
import matplotlib.pyplot as plt

x = [0,10,20,30,40,50,60,70,80,90]
for i in x:
    t = mpl.markers.MarkerStyle(marker='o')
    t._transform = t.get_transform().rotate_deg(-i)
    marker_style = dict(color='b',  markerfacecoloralt='orange', markeredgecolor='w', markersize=25,
                        marker='o' )    
    plt.plot(i, i, marker=(2, 0, -i), c='k',markersize=30, linestyle='None')
    plt.plot(i, i, marker=(3, 0, -i), c='k',markersize=10, linestyle='None')
    plt.plot(i, i+20,fillstyle='top', **marker_style)
plt.margins(0.15); plt.grid();plt.show()

I have tried without success:

marker_style = dict(....., marker=(3, 3, -i) ) 
or
marker_style = dict(....., marker=t ) 
or
plt.plot(i, i+20,fillstyle='top', marker=(3, 3, -i) 

Thanks if you know and tell how to put the things together ! A solution with plt.scatter() would be fine too.

Answer 1

我不知道是否可以使用标记或MarkerStyle来完成，文档仅指定如何填充除以一半的符号。您可以通过将2个半圆放在一起并相应地旋转它们来模仿这种行为。

import matplotlib.pyplot as plt
import matplotlib as mpl

plt.figure(1)

x = [0,10,20,30,40,50,60,70,80,90]

ax=plt.gca()
rot=0

for i in x:

    HalfA=mpl.patches.Wedge((i, i+20), 5,theta1=0-rot,theta2=180-rot, color='r')
    HalfB=mpl.patches.Wedge((i, i+20), 5,theta1=180-rot,theta2=360-rot, color='b')

    rot=rot+360/len(x)

    ax.add_artist(HalfA)
    ax.add_artist(HalfB)

    ax.plot(i, i, marker=(2, 0, -i), c='k',markersize=30, linestyle='None')
    ax.plot(i, i, marker=(3, 0, -i), c='k',markersize=10, linestyle='None')


ax.set_xlim((-10, 110))
ax.set_ylim((-10, 130))