Question

我要复制到另一个文件夹（destination_folder）的一个文件夹（图像）中有一堆jpg。复制它们时，我希望将jpg文件重命名如下：filename1_red.jpg，filename2_red.jpg（即在末尾加上_red后缀）

到目前为止，我有以下内容：

import os
images = os.listdir('C:/Users/Admin-dsc/Documents/.../buses and motorcycles')
destination_folder = 'C:/Users/Admin-dsc/Documents/.../Buses'

for img in images: 
    filename = os.path.basename(img)
    copyfile(img, os.path.join(destination_folder, filename))

问题1：我收到一个我不明白的错误-我该如何解决：

FileNotFoundError: [Errno 2] No such file or directory: 'RWG074059_2_o.jpg'

问题2：我不确定如何获得后缀。

有人可以帮忙吗？

Answer 1

os.listdir仅返回指定文件夹中文件的文件名，而不返回文件的完整路径。因此，您需要使用img连接源文件夹路径：

import os
from shutil import copyfile

source_folder = 'C:/Users/Admin-dsc/Documents/.../buses and motorcycles'
destination_folder = 'C:/Users/Admin-dsc/Documents/.../Buses'
images = os.listdir(source_folder)

for img in images:
    filename, ext = os.path.splitext(img)
    filename = filename + '_red' + ext
    copyfile(os.path.join(source_folder, img), os.path.join(destination_folder, filename))

Answer 2

如何调试此错误：

import os

directory = 'C:/Users/Admin-dsc/Documents/.../buses and motorcycles'
images = os.listdir(directory) 

for img in images: 
    print(img)
    filename = os.path.basename(img)
    print(filename)

输出：

main.py
main.py

您看到的内容：

您看到listdir()仅返回文件名。您需要再次在源文件夹之前。

如何解决：

import os

directory = './'
destination_folder = 'C:/Users/Admin-dsc/Documents/.../Buses'
images = os.listdir(directory) 

for img in images: 
    print(img)
    filename = os.path.basename(img)
    print(filename)

    # prepend path again
    source = os.path.join(directory,img)
    target = os.path.join(destination_folder,img)

    print(source, "=>",  target)

    # copyfile(source, target)

输出：

 ./main.py => C:/Users/Admin-dsc/Documents/.../Buses/main.py

Answer 3

img仅包含图像名称，而不包含完整的路径信息。

当您指定源图像时，请构建一个中止路径：

import os
source_folder = 'C:/Users/Admin-dsc/Documents/.../buses and motorcycles'
images = os.listdir(source_folder)
destination_folder = 'C:/Users/Admin-dsc/Documents/.../Buses'

for img in images: 
    filename = os.path.basename(img)
    copyfile(os.path.join(source_folder, img), os.path.join(destination_folder, filename))

从文件夹复制图像

3 个答案: