Question

我经常在python异常中这样做：

try:
    <some process>
except Exception as e:
    print(e)

当我希望脚本继续运行但仍然告诉我有错误时，这对我有帮助。但是，print(e)并不像我让异常引发那样详细。有什么办法可以在不引发异常的情况下更详细地显示错误？

Answer 1

有多种打印回溯信息的方法。

如评论中所述，您可以使用traceback模块的print_exc函数

try:
    1 / 0
except Exception:
    traceback.print_exc()

Traceback (most recent call last):
  File "exes.py", line 10, in <module>
    1 / 0
ZeroDivisionError: division by zero

如果使用日志记录模块，则logging.exception函数将自动记录回溯，作为ERROR级别日志消息的一部分。

try:
    2 / 0 
except Exception:
    logging.exception('Something went wrong')

ERROR:root:Something went wrong
Traceback (most recent call last):
  File "exes.py", line 15, in <module>
    2 / 0
ZeroDivisionError: division by zero

如果您希望以其他日志级别记录回溯，则可以将exc_info=True传递给日志功能以记录回溯。

try:
    3 / 0 
except Exception:
    logging.warning('Something went wrong.', exc_info=True)

WARNING:root:Something went wrong.
Traceback (most recent call last):
  File "exes.py", line 20, in <module>
    3 / 0
ZeroDivisionError: division by zero

如何获得详细的异常？

1 个答案: