Question

我正在尝试将2个对象数组合并为一个对象数组，同时保持save()在合并数组中的顺序。

在arr1中存在arr1中存在的internalName键。 arr2中的type键代表arr1中键的值-例如，arr2中的avg类型应映射到arr1具有相同average的{{1}}的密钥。

arr2

预期结果：

internalName

我已经使用带有嵌套const arr1 = [ {internalName: "14_17_years_old", type: "avg"}, {internalName: "14_17_years_old", type: "sum"}, {internalName: "18_24_years_old", type: "avg"}, {internalName: "25_34_years_old", type: "sum"}, {internalName: "35_44_years_old", type: "avg"}, {internalName: "35_44_years_old", type: "sum"}, {internalName: "activity_attendance", type: "sum"}, ]; const arr2 = [ {average: 83, count: 7, internalName: "14_17_years_old", name: "14-17 Years Old", sum: 578}, {average: 168, count: 11, internalName: "18_24_years_old", name: "18-24 Years Old", sum: 1850}, {average: 193, count: 11, internalName: "25_34_years_old", name: "25-34 Years Old", sum: 2126}, {average: 237, count: 10, internalName: "35_44_years_old", name: "35-44 Years Old", sum: 2370}, {average: 828, count: 28, internalName: "activity_attendance", name: "Activity Attendance", sum: 23190} ];的{{1}}开始了这条路线，但没有返回任何内容。

const expected = [
  {internalName: "14_17_years_old", name: "14-17 Years Old", type: "avg", value: 83},
  {internalName: "14_17_years_old", name: "14-17 Years Old", type: "sum", value: 578},
  {internalName: "18_24_years_old", name: "18-24 Years Old", type: "avg", value: 168},
  {internalName: "25_34_years_old", name: "25-34 Years Old", type: "sum", value: 2126},
  {internalName: "35_44_years_old", name: "35-44 Years Old", type: "avg", value: 237},
  {internalName: "35_44_years_old", name: "35-44 Years Old", type: "sum", value: 2370},
  {internalName: "activity_attendance", name: "Activity Attendance", type: "sum", value: 23190},
];

实际上有一个两部分的问题-如何在没有太多代码的情况下完成此任务？

Answer 1

您可以使用arr2进行查找，以允许恒定时间检索对象。然后，您可以map遍历arr1中的项目并构建新结果数组的对象：

const arr1 = [{internalName: "14_17_years_old", type: "avg"},{internalName: "14_17_years_old", type: "sum"},{internalName: "18_24_years_old", type: "avg"},{internalName: "25_34_years_old", type: "sum"},{internalName: "35_44_years_old", type: "avg"},{internalName: "35_44_years_old", type: "sum"},{internalName: "activity_attendance", type: "sum"},];
const arr2 = [{average: 83, count: 7, internalName: "14_17_years_old", name: "14-17 Years Old", sum: 578},{average: 168, count: 11, internalName: "18_24_years_old", name: "18-24 Years Old", sum: 1850},{average: 193, count: 11, internalName: "25_34_years_old", name: "25-34 Years Old", sum: 2126},{average: 237, count: 10, internalName: "35_44_years_old", name: "35-44 Years Old", sum: 2370},{average: 828, count: 28, internalName: "activity_attendance", name: "Activity Attendance", sum: 23190}];

let lookup = arr2.reduce((map, {internalName, average:avg, sum, name }) => map.set(internalName, {avg, sum, name}), new Map)

let res = arr1.map(({internalName, type}) => ({
       internalName, 
       type, 
       value: lookup.get(internalName)[type],
       name: lookup.get(internalName)['name']
  }))

console.log(res)

复杂对象数组合并

1 个答案: