Question

我有一些服务，我想为其创建一个共享的基类...但是，当我安装测试子类服务时，它会失败，并出现无用的错误。

代码如下：

import servicemanager
import win32serviceutil
import sys
import win32service
import win32event

class PythonServiceBase(win32serviceutil.ServiceFramework):
    _svc_name_ = "SmallestPythonService"
    _svc_display_name_ = "The smallest possible Python Service"
    def __init__(self, args):
        win32serviceutil.ServiceFramework.__init__(self, args)
        # Create an event which we will use to wait on.
        # The "service stop" request will set this event.
        self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)

    def SvcStop(self):
        # Before we do anything, tell the SCM we are starting the stop process.
        self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
        # And set my event.
        win32event.SetEvent(self.hWaitStop)

    def SvcDoRun(self):
        # We do nothing other than wait to be stopped!
        win32event.WaitForSingleObject(self.hWaitStop, win32event.INFINITE)


class BaselineService(PythonServiceBase):
    _svc_name_ = "SmallestPythonService2"
    _svc_display_name_ = "The smallest possible Python Service2"
    def __init__(self, args):
        super(BaselineService, self).__init__(args)


if __name__ == '__main__':
    if len(sys.argv) == 1:
        servicemanager.Initialize()
        servicemanager.PrepareToHostSingle(BaselineService)
        servicemanager.StartServiceCtrlDispatcher()
    else:
        win32serviceutil.HandleCommandLine(BaselineService)

这是我创建和安装的方式：

pyinstaller -F --debug --hidden-import=win32timezone Baseline\baseline_service.py

dist\baseline_service.exe install && net start SmallestPythonService2

CMD输出中没有回溯，但显示如下：

The The smallest possible Python Service2 service is starting.
The The smallest possible Python Service2 service could not be started.

A service specific error occurred: 1.

More help is available by typing NET HELPMSG 3547.

内部事件查看器中，我看到以下内容：

- <Event xmlns="http://schemas.microsoft.com/win/2004/08/events/event">
- <System>
  <Provider Name="Python Service" /> 
  <EventID Qualifiers="49152">10</EventID> 
  <Level>2</Level> 
  <Task>0</Task> 
  <Keywords>0x80000000000000</Keywords> 
  <TimeCreated SystemTime="2019-01-17T22:43:16.954038000Z" /> 
  <EventRecordID>76457</EventRecordID> 
  <Channel>Application</Channel> 
  <Computer>DESKTOP-IM94TC5</Computer> 
  <Security /> 
  </System>
- <EventData>
  <Data><Error getting traceback - traceback.print_exception() failed</Data> 
  </EventData>
  </Event>

pyinstaller不能将子类行为准确地传递到EXE上下文吗？

如果是，以下替代策略的利弊是什么？

从“ ServiceUtil”模块导入所有共享方法以与我的各种服务一起使用
在运行真实服务的同一台计算机上运行“ ServiceHelper”，并在每个服务的__init__上运行，您应咨询此ServiceHelper以获取其共享行为（如DoRun和Stop方法等）

Answer 1

Do！问题出在这里：

代替调用（仅适用于Python 2）：

super(BaselineService, self).__init__(args)

...我直接调用了父类，它起作用了：

PythonServiceBase.__init__(self, args)

这也有效（我没有正确调用super。仅适用于Python 3）：

super().__init__(args)

来源：An example

是否可以继承win32serviceutil.ServiceFramework的子类？

1 个答案: