Question

我有一个t-sql脚本正在提取我们网站的成员，但是我遇到了使用*，＆amp;或商业名称中的数字。

我有以下数据：

''Dream A Little Dream''
***Unique Business Card/Sign/Logo Designs***
3D Visual Creations
50dollarbanner.com
etc..

我在页面顶部有字母表字母，用户可以单击“A”例如它列出所有以“A”开头的用户是否有办法让另一个用于“0”例如它将列出所有以数字或奇怪字符开头的成员：

这是我的测试脚本：

DECLARE @TotalPages INT
DECLARE @UserName varchar(50)
DECLARE @PG INT
DECLARE @PageSize INT
SET @UserName = 'Z'
SET @PG = 1
SET @PageSize = 70
BEGIN
    SELECT @TotalPages = COUNT(*)/@PageSize
    FROM Member
    WHERE (sbuser.sf_GetDisplayName(FirstName, LastName, BusinessName, DisplayNameTypeID) LIKE @UserName + '%')
    AND UserName IS NOT NULL;

    WITH FindSBMembers AS
    (
        SELECT ROW_NUMBER() OVER(ORDER BY Claimed DESC, sbuser.sf_MemberHasAvatar(MemberID) DESC) AS RowNum,
        MemberID,                                                -- 1
        UserName,                                                -- 2
        PrCity,                                                  -- 3
        PrStateID,                                               -- 4
        sbuser.sf_MemberHasImages(MemberID) AS MemberHasImages,  -- 5
        sbuser.sf_MemberHasVideo(MemberID) AS MemberHasVideo,    -- 6
        sbuser.sf_MemberHasAudio(MemberID) AS MemberHasAudio,    -- 7
        sbuser.sf_GetDisplayName(FirstName, LastName, BusinessName, DisplayNameTypeID) AS DisplayName,          -- 8
        ProfileTypeID,                                           -- 9
        Zip,                                                   -- 10
        PhoneNbr,                                                -- 11
        PrPhone,                                                 -- 12
        Claimed,                                                 -- 13
        @TotalPages AS TotalPages,                               -- 14
        City                                                     -- 15
        FROM Member
        WHERE (sbuser.sf_GetDisplayName(FirstName, LastName, BusinessName, DisplayNameTypeID) LIKE @UserName + '%')
        AND UserName IS NOT NULL
        -- AND MemberID <> @MemberID
    )
    SELECT * 
    FROM FindSBMembers
    WHERE RowNum BETWEEN (@PG - 1) * @PageSize AND @PG * @PageSize
    ORDER BY Claimed DESC
END

以下是包含脚本的详细信息：

set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
GO

ALTER FUNCTION [sbuser].[sf_GetDisplayName](
@FirstName varchar(50),
@LastName varchar(50),
@BusinessName varchar(50),
@DisplayNameTypeID int)
RETURNS varchar(150) WITH schemabinding

AS

BEGIN
DECLARE @OUT varchar(150)
SET @OUT = ''
SET @FirstName = UPPER(LEFT(LTRIM(RTRIM(@FirstName)), 1)) + RIGHT(LTRIM(RTRIM(@FirstName)), LEN(LTRIM(RTRIM(@FirstName))) - 1)
SET @LastName = UPPER(LEFT(LTRIM(RTRIM(@LastName)), 1)) + RIGHT(LTRIM(RTRIM(@LastName)), LEN(LTRIM(RTRIM(@LastName))) - 1)
SET @BusinessName = UPPER(LEFT(LTRIM(RTRIM(@BusinessName)), 1)) + RIGHT(LTRIM(RTRIM(@BusinessName)), LEN(LTRIM(RTRIM(@BusinessName))) - 1)
IF @DisplayNameTypeID = 2   -- FIRST / LAST NAME
    BEGIN
        SET @OUT = @LastName + ', ' + @FirstName
    END
IF @DisplayNameTypeID = 3 -- FIRST NAME / LAST INITIAL
    BEGIN
        SET @OUT = @FirstName + ' ' + LEFT(@LastName,1) + '.'
    END
IF @DisplayNameTypeID = 4 -- BUSINESS NAME
    BEGIN
        SET @OUT = @BusinessName + ''
    END
RETURN @OUT
END

非常感谢你的帮助。

此致保罗

Answer 1

如果要包含输入参数@UserName为'0'的非字母起始字符的所有条目，那么您可以尝试下面的WHERE子句（未测试）吗？

这将允许您拥有一个“Misc”类别，您可以通过使用@UserName ='0'

调用该过程来检索该类别

 WHERE (     
            (  sbuser.sf_GetDisplayName(FirstName, LastName, BusinessName, 
                                  DisplayNameTypeID) LIKE @UserName + '%'
            )         
         OR
            (
               PatIndex(‘[^A-Za-z]%‘,
                  sbuser.sf_GetDisplayName(FirstName, LastName, BusinessName, 
                                           DisplayNameTypeID)  > 0  ) 
               AND 
               @UserName = '0'
            )         
       )
       AND UserName IS NOT NULL

Answer 2

在开头使用类似的内容（在使用@UserName的查询之前）：

IF @UserName = '0' SET @UserName = '[^a-z]';

如果您的排序规则区分大小写，那么您可能应该使用'[^A-Za-z]'。

非字母字符

2 个答案: