Question

我正在从事一个项目，该项目涉及创建与大学名册有关的许多课程（名册，学生，枚举类型学位等）。我有一个我需要解析的学生数据列表，包含字符串和整数。我正在使用stoi转换我的整数，但我不断收到错误“以类型为std :: invalid_argument的未捕获异常终止：stoi：无转换”。我真的很想念这里吗？

我尝试重新排列，并从其他几种方法切换到stringstream，但是我仍然遇到相同的错误。

const string studentData[] =
        {"A1, John, Smith, John1989@gm ail.com, 20, 30, 35, 30, 
SECURITY",
         "A2, Suzan, Erickson, Erikson_1990@gmailcom, 19, 50, 30, 40, 
NETWORK",
         "A3, Jack, Napoli, The_lawyer99yahoo.com, 19, 20, 40, 33, 
SECURITY"
         "A4, Erin, Black, Erin.black@comcast.net, 22, 50, 58, 40, 
SECURITY",
         "A5, Martin, Mart, martin.mart@comcast.net, 22, 30, 32, 35, 
SOFTWARE"};




//add each student to the classRoster

for (int i = 0; i < 5; i++) {

//create stringstream to parse data

stringstream inSS(studentData[i]);

//create an empty vector

vector<string> studentInfo;

//check that stringstream is good and append values from 
    studentData to the studentInfo

while (inSS.good()) {
string segment;
getline(inSS, segment, ',');
studentInfo.push_back(segment);
}

Degree degree;
string studentDegreeProgram = studentInfo.at(8);

if (studentDegreeProgram == "SECURITY") {
        degree = SECURITY;
}
else if (studentDegreeProgram == "NETWORKING") {
        degree = NETWORKING;
}
else {
        degree = SOFTWARE;
}

classRoster->Add(studentInfo.at(0), studentInfo.at(1), 
studentInfo.at(2), studentInfo.at(3), stoi(studentInfo.at(4)), 
stoi(studentInfo.at(5)), stoi(studentInfo.at(6)), 
stoi(studentInfo.at(7)), degree);
}

Answer 1

问题是，当您将没有整数值的字符串转换为int时，您尝试将其转换。使用stoi（）时，“ SECURITY”是否具有等效的int值？否。使用stoi（）时，“ 5”是否具有等效的int值？是的。

使用stringstream解析数据时发生错误（错误：没有转换）？

1 个答案: