Question

我是Python的新手，有一定的C语言背景。我想用try设置while循环-除了-else结构。当尝试验证数据类型时（使用ValueError除外），例如提示用户输入整数，我已经成功完成了此操作。但是，对于此程序，用户输入了一个字符串，程序需要根据字符串列表检查该字符串，如果不在列表中，请再次询问用户。到目前为止，我的代码可以运行，但是无论用户输入如何，循环都会中断。现在是这里：

senses = ["touch", "smell", "sight", "hearing", "taste"]


while True:
    try:
        choice = input("What is your favorite sense? ")

    except: 
        if choice not in senses:
            print("Sorry, I don't think that's a sense")
            #try again, return to start of loop
            continue 
    else:
        break

最初我的代码看起来像这样并且可以正常工作，但是输入法存在冗余的问题：

senses = ["touch", "smell", "sight", "hearing", "taste"]
choice = input("What is your favorite of the 5 human senses:")

while choice not in senses:

    choice =input("What is your favorite of the 5 human senses")

Answer 1

关于个人喜好/问题的适合性，但是我倾向于使用类似的东西

senses = ["touch", "smell", "sight", "hearing", "taste"]
choice = ""

while choice not in senses:
    choice =input("What is your favorite of the 5 human senses")

这会将choice初始化为senses中没有的内容，从而强制执行第一个循环

Answer 2

我会这样写：

this::hashCode

这样，您只在一个地方问问题。 senses = {"touch", "smell", "sight", "hearing", "taste"} while True: choice = input("What is your favorite of the 5 human senses? ") if choice in senses: break的意思是“永远做这件事”，一旦满足条件，while True就会停止循环。

使用While循环检查用户的输入（字符串）是否属于列表？

2 个答案: